The rate of effusion of NO2 gas through a porous barrier is observed to be 4.28 x 10-4 mol/h. Under the same conditions, the rate of effusion of O3 gas would be _____ mol/h. For reference, here is a completely different problem from this one, but with the same idea.
The rate of effusion of NO2 gas through a porous barrier is observed to be 4.28 x 10-4 mol/h. Under the same conditions, the rate of effusion of O3 gas would be _____ mol/h. For reference, here is a completely different problem from this one, but with the same idea.
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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The rate of effusion of NO2 gas through a porous barrier is observed to be 4.28 x 10-4 mol/h.
Under the same conditions, the rate of effusion of O3 gas would be _____ mol/h.
For reference, here is a completely different problem from this one, but with the same idea.
Transcribed Image Text:The rate of effusion of H2 gas through a porous barrier is observed to be 3.33 x 10-4 mol/h.
Under the same conditions, the rate of effusion of Ne gas would be
mol/h.
At the same conditions, Graham's law states that the rate of effusion of a gas is inversely proportional to the square root of the molar mass.
Rate of effusion = constant x
M
For two different gases at the same conditions:
(M of 1)
(M of 2)
Rate 2
Rate 1
In this case:
1 = H2, M = 2.02 g/mol, rate of effusion = 3.33 x 10-4 molh
2 = Ne, M = 20.2 g/mol
Rate Ne
(2.02 g/mol)
3.33 x 10-4 mol/h
(20.2 g/mol)
(2.02 g/mol)
Rate Ne = 3.33 x 10-4 mol/h x
= 1.05 x 10-4 mol/h
(20.2 g/mol)
Note that the molar mass of Ne is higher than the molar mass of H2 and that the rate of effusion of Ne is lower than the rate of effusion of H2.
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