The label on a tank of gas of unknown origin had been lost. To determine its identity (molecular weight) a certain volume of it took 121.3 seconds to effuse through a porous partition. Under identical conditions C3H 8 effused through the hole in 64.95 seconds. What is the molar mass of the unknown gas? Remember that effusion rate and time are inversely proportional to each other. Key Concept:Kinetic theory of gase: rate of effusion. Strategy: Rate of effusion, u = k/M 1/2 where k is a constant.
The label on a tank of gas of unknown origin had been lost. To determine its identity (molecular weight) a certain volume of it took 121.3 seconds to effuse through a porous partition. Under identical conditions C3H 8 effused through the hole in 64.95 seconds. What is the molar mass of the unknown gas? Remember that effusion rate and time are inversely proportional to each other. Key Concept:Kinetic theory of gase: rate of effusion. Strategy: Rate of effusion, u = k/M 1/2 where k is a constant.
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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The label on a tank of gas of unknown origin had been lost. To determine its identity (molecular weight) a certain volume of it took 121.3 seconds to effuse through a porous partition. Under identical conditions C3H 8 effused through the hole in 64.95 seconds. What is the molar mass of the unknown gas? Remember that effusion rate and time are inversely proportional to each other.
Key Concept:Kinetic theory of gase: rate of effusion.
Strategy: Rate of effusion, u = k/M 1/2 where k is a constant.
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