The rate of a certain reaction is given by the following rate law: rate= = K[N₂] [H₂]² Use this information to answer the question below. At a certain concentration of N₂ and H₂, the initial rate of reaction is 0.340 M/s. What would the initial rate of the reaction be if the concentration of N₂ were halved? Round your answer to 3 significant digits. 04/1

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### Reaction Rate Law

The rate of a certain reaction is given by the following rate law:

\[ \text{rate} = k [\text{N}_2] [\text{H}_2]^2 \]

Use this information to answer the question below.

---

**Question:**

At a certain concentration of \(\text{N}_2\) and \(\text{H}_2\), the initial rate of reaction is \(0.340 \, M/s\). What would the initial rate of the reaction be if the concentration of \(\text{N}_2\) were halved? Round your answer to 3 significant digits.

---

**Answer Section:**

\[ \, \, M/s \]
Transcribed Image Text:### Reaction Rate Law The rate of a certain reaction is given by the following rate law: \[ \text{rate} = k [\text{N}_2] [\text{H}_2]^2 \] Use this information to answer the question below. --- **Question:** At a certain concentration of \(\text{N}_2\) and \(\text{H}_2\), the initial rate of reaction is \(0.340 \, M/s\). What would the initial rate of the reaction be if the concentration of \(\text{N}_2\) were halved? Round your answer to 3 significant digits. --- **Answer Section:** \[ \, \, M/s \]
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