The rate of a certain reaction is given by the following rate law: rate= = K[N₂] ² [H₂]² Use this information to answer the questions below. What is the reaction order in N₂? What is the reaction order in H₂? What is overall reaction order? At a certain concentration of N₂ and H₂, the initial rate of reaction is 7.0 x 105 M/s. What would the initial rate of the reaction be if the concentration of N₂ were halved? Round your answer to 2 significant digits. The rate of the reaction is measured to be 41.0 M/s when [N₂] = 0.39 M and [H₂] = 0.78 M. Calculate the value of the 0 0 0-- -3 S - 1
The rate of a certain reaction is given by the following rate law: rate= = K[N₂] ² [H₂]² Use this information to answer the questions below. What is the reaction order in N₂? What is the reaction order in H₂? What is overall reaction order? At a certain concentration of N₂ and H₂, the initial rate of reaction is 7.0 x 105 M/s. What would the initial rate of the reaction be if the concentration of N₂ were halved? Round your answer to 2 significant digits. The rate of the reaction is measured to be 41.0 M/s when [N₂] = 0.39 M and [H₂] = 0.78 M. Calculate the value of the 0 0 0-- -3 S - 1
Chemistry: An Atoms First Approach
2nd Edition
ISBN:9781305079243
Author:Steven S. Zumdahl, Susan A. Zumdahl
Publisher:Steven S. Zumdahl, Susan A. Zumdahl
Chapter11: Chemical Kinetics
Section: Chapter Questions
Problem 5RQ
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![### Reaction Rate Law
The rate of a certain reaction is given by the following rate law:
\[
\text{rate} = k [N_2]^2 [H_2]^2
\]
Use this information to answer the questions below.
#### Questions:
1. **What is the reaction order in \(N_2\)?**
- **Answer:**
2. **What is the reaction order in \(H_2\)?**
- **Answer:**
3. **What is the overall reaction order?**
- **Answer:**
4. **At a certain concentration of \(N_2\) and \(H_2\), the initial rate of reaction is \(7.0 \times 10^5 \, M/s\). What would the initial rate of the reaction be if the concentration of \(N_2\) were halved? Round your answer to 2 significant digits.**
\[
\text{Answer:} \quad \boxed{ \, M/s \, }
\]
5. **The rate of the reaction is measured to be \(41.0 \, M/s\) when \([N_2] = 0.39 \, M\) and \([H_2] = 0.78 \, M\). Calculate the value of the rate constant. Round your answer to 2 significant digits.**
\[
k = \boxed{ \, M^{-3} \cdot s^{-1} \, }
\]
#### Explanation of Graphs or Diagrams
There are no graphs or diagrams in the provided text. This section includes only mathematical representations and questions for students to solve based on given reaction data.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F20b515c9-5e3a-448e-90a2-ac3b562e1523%2F9976df96-ab3c-45af-aec1-d20d2ab4091b%2Fs55znup_processed.jpeg&w=3840&q=75)
Transcribed Image Text:### Reaction Rate Law
The rate of a certain reaction is given by the following rate law:
\[
\text{rate} = k [N_2]^2 [H_2]^2
\]
Use this information to answer the questions below.
#### Questions:
1. **What is the reaction order in \(N_2\)?**
- **Answer:**
2. **What is the reaction order in \(H_2\)?**
- **Answer:**
3. **What is the overall reaction order?**
- **Answer:**
4. **At a certain concentration of \(N_2\) and \(H_2\), the initial rate of reaction is \(7.0 \times 10^5 \, M/s\). What would the initial rate of the reaction be if the concentration of \(N_2\) were halved? Round your answer to 2 significant digits.**
\[
\text{Answer:} \quad \boxed{ \, M/s \, }
\]
5. **The rate of the reaction is measured to be \(41.0 \, M/s\) when \([N_2] = 0.39 \, M\) and \([H_2] = 0.78 \, M\). Calculate the value of the rate constant. Round your answer to 2 significant digits.**
\[
k = \boxed{ \, M^{-3} \cdot s^{-1} \, }
\]
#### Explanation of Graphs or Diagrams
There are no graphs or diagrams in the provided text. This section includes only mathematical representations and questions for students to solve based on given reaction data.
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