The rate law for the reaction of NO with Cl2 was found to be 2 NO() + Cl2g) → 2 NOCIg) Rate= k[NO]² [Cl2] a. What is the order of the reaction with respect to NO? With respect to Cl2? b. Suppose that you triple the concentration of NO and simultaneously decrease the concentration of Cl2 by a factor of 8. Will the reaction be faster or slower under the new conditions? How much faster or slower? (Assume that the temperature is the same in both sets of conditions.)

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The rate law for the reaction of NO with Cl2 was found to be
2 NO) + Cl2e) → 2 NOCle) Rate= k[NO]² [Cl2]
a. What is the order of the reaction with respect to NO? With
respect to Cl,?
b. Suppose that you triple the concentration of NO and
simultaneously decrease the concentration of Cl, by a factor of
8. Will the reaction be faster or slower under the new
conditions? How much faster or slower? (Assume that the
temperature is the same in both sets of conditions.)
Transcribed Image Text:The rate law for the reaction of NO with Cl2 was found to be 2 NO) + Cl2e) → 2 NOCle) Rate= k[NO]² [Cl2] a. What is the order of the reaction with respect to NO? With respect to Cl,? b. Suppose that you triple the concentration of NO and simultaneously decrease the concentration of Cl, by a factor of 8. Will the reaction be faster or slower under the new conditions? How much faster or slower? (Assume that the temperature is the same in both sets of conditions.)
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