The rate constant of a chemical reaction increased from 0.100 s−1 to 3.20 s−1 upon raising the temperature from 25.0 ∘C to 35.0 ∘C. A) Calculate the value of (1/T2 - 1/T1) where T1 is the initial temperature and T2 is the final temperature. Express your answer numerically. B) Calculate the value of ln(k1/k2) where k1 and k2 correspond to the rate constants at the initial and the final temperatures as defined in part A. Express your answer numerically. C) What is the activation energy of the reaction? Express your answer numerically in kilojoules per mole.

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The rate constant of a chemical reaction increased from 0.100 s−1 to 3.20 s−1 upon raising the temperature from 25.0 ∘C to 35.0 ∘C.

 

A) Calculate the value of (1/T2 - 1/T1) where T1 is the initial temperature and T2 is the final temperature.
Express your answer numerically.
 
 
B) Calculate the value of ln(k1/k2) where k1 and k2 correspond to the rate constants at the initial and the final temperatures as defined in part A.
Express your answer numerically.
 
C) What is the activation energy of the reaction?
Express your answer numerically in kilojoules per mole.
Learning Goal:
To use the Arrhenius equation to calculate the
activation energy.
As temperature rises, the average kinetic energy of
molecules increases. In a chemical reaction, this
means that a higher percentage of the molecules
possess the required activation energy, and the
reaction goes faster. This relationship is shown by the
Arrhenius equation
k= Ae-Ea/RT
where k is the rate constant, A is the frequency
factor, Ea is the activation energy, R= 8.3145
J/(K. mol) is the gas constant, and T is the Kelvin
temperature. The following rearranged version of the
equation is also useful:
(:)= (#)(±-4)
k1
In
k2
Ea
R
T2
where ki is the rate constant at temperature T1, and
k2 is the rate constant at temperature T3.
Transcribed Image Text:Learning Goal: To use the Arrhenius equation to calculate the activation energy. As temperature rises, the average kinetic energy of molecules increases. In a chemical reaction, this means that a higher percentage of the molecules possess the required activation energy, and the reaction goes faster. This relationship is shown by the Arrhenius equation k= Ae-Ea/RT where k is the rate constant, A is the frequency factor, Ea is the activation energy, R= 8.3145 J/(K. mol) is the gas constant, and T is the Kelvin temperature. The following rearranged version of the equation is also useful: (:)= (#)(±-4) k1 In k2 Ea R T2 where ki is the rate constant at temperature T1, and k2 is the rate constant at temperature T3.
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