The rate constant for the formation of hydrogen iodide from the elements H2(g) + I2(g) → 2HI(g) is 2.7 x 10 L/(mol-s) at 600 K and 3.5 × 10 3 L/(mol-s) at 650K. a. Find the activation energy E. 166000 V J/mol b. Then calculate the rate constant at 678 K. *L/(mol•s)
The rate constant for the formation of hydrogen iodide from the elements H2(g) + I2(g) → 2HI(g) is 2.7 x 10 L/(mol-s) at 600 K and 3.5 × 10 3 L/(mol-s) at 650K. a. Find the activation energy E. 166000 V J/mol b. Then calculate the rate constant at 678 K. *L/(mol•s)
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Chapter1: Chemical Foundations
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![The rate constant for the formation of hydrogen iodide from the elements
H2(g) + I2(g) → 2HI(g)
is 2.7 x 104 L/(mol·s) at 600 K and 3.5 × 103 L/(mol-s) at 650 K.
a. Find the activation energy E.
166000
V J/mol
b. Then calculate the rate constant at 678 K.
* L/(mol•s)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F0448498f-fc6a-450b-b87e-40083153e575%2F914b4ac5-29fe-4f45-8ecf-bde6d372b356%2Ftcrtz4_processed.jpeg&w=3840&q=75)
Transcribed Image Text:The rate constant for the formation of hydrogen iodide from the elements
H2(g) + I2(g) → 2HI(g)
is 2.7 x 104 L/(mol·s) at 600 K and 3.5 × 103 L/(mol-s) at 650 K.
a. Find the activation energy E.
166000
V J/mol
b. Then calculate the rate constant at 678 K.
* L/(mol•s)
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