The rate at which customers are served at an airport check-in counter is a Poisson process with a with a rate of 7.4 per hour. Suppose that a random sample of 50 customers is observed. The probability that the average waiting for these 50 customers is less than 8 minutes is given by, P( X ¯ < 8) = P(Z < a), where Z is the standard normal variable. What is the value of a? Please report your answer in 3 decimal places.

Q: The average daily sales(X) of a branch are $500 and standard deviation is $51. Assuming the…

A: Answer: From the given data, The daily sales (X) are normally distributed with mean (μ) = $ 500…

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A: From a normal distribution, Mean = 54 Standard deviation = 6

Q: A normal distribution has u = 30 and o = 5.

A: Given that, Mean = 30 Standard deviation = 5 Z score = 1.3

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A: Given: The mean of the processing time μ=23 sec The standard deviation σ=2 sec.

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A:

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A: Given ,  IQ is a score (X) that is transformed so that it has a normal distribution. Mean = x¯ = 100…

Q: ore on last attempt:   0.5 out of 1 (parts:  0.17/0.17,  0/0.17,  0.17/0.17,  0.17/0.17,  0/0.17,…

A: Hello there! there are more than three subparts in the question. According to our policies we cannot…

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A: Given, Assume that females have pulse rates that are normally distributed with a mean of μ=74.0…

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A: Solution

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A: We have to find given probability.

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Q: The average number of miles (in thousands) that a car's tire will function before needing…

A: answer is explained below

Q: The average number of miles (in thousands) that a car's tire will function before needing…

A: Note: Please repost remaining subparts as i can author only 3 sub-parts as per my policy. Given…

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Q: replacement is 66 and the standard deviation is 19. Suppose that 49 randomly selected ires are…

A: We have given that.   X~N( μ , ?^2 )   μ =  66 , ? = 19  , n= 49   Z-score =( x - μ )/?…

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A: “Since you have posted multiple questions with multiple sub parts, we will provide the solution only…

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A: Given that the mean of the distribution is = 5% and standard deviation=1%  So the sample mean= 5%…

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A: It is given that the mean is 15 and the standard deviation is 3.

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Q: he mean daily production of a herd of cows is assumed to be normally distributed with a mean of 39…

A: Given data,μ=39σ=2.4

Q: 6. Use R: Suppose the yearly income of people in Minnesota is normally distributed with mean 45700…

A: The given mean is 45700 and standard deviation is 2830.

Q: Assume that adults have IQ scores that are normally distributed with a mean of μ=100and a standard…

A: From the provided information, Mean (µ) = 100 Standard deviation (σ) = 20 Let X be a random variable…

Estimation

A new framework of data analysis where the new statistical methods are used for interpreting the results and analyzing the data is known as estimation in statistics.