The rate at which a powdered chemical dissolves is jointly proportional to: amount of undissolved portion and the difference in concentration between the actual and saturated solution (Ca and Cs respectively), that is dx/dt = kx (Cs – Ca), and Ca can expressed as the ratio of the difference between the initial amount and the amount of chemical present at any time “t” to the original volume of water. Initially, 4.5 kg of the chemical is agitated with 0.3785 m3 of H2O, and after an hour the undissolved portion reduced by 40.40%. If a saturated solution contains 0.0909 kg of chemical per gallon, find the amount of this chemical which is undissolved after 2 hours, in kilograms. Round off the values along the process to 4 decimal places to avoid deviation from the correct answer in the choices.
The rate at which a powdered chemical dissolves is jointly proportional to: amount of undissolved portion and the difference in concentration between the actual and saturated solution (Ca and Cs respectively), that is dx/dt = kx (Cs – Ca), and Ca can expressed as the ratio of the difference between the initial amount and the amount of chemical present at any time “t” to the original volume of water. Initially, 4.5 kg of the chemical is agitated with 0.3785 m3 of H2O, and after an hour the undissolved portion reduced by 40.40%. If a saturated solution contains 0.0909 kg of chemical per gallon, find the amount of this chemical which is undissolved after 2 hours, in kilograms. Round off the values along the process to 4 decimal places to avoid deviation from the correct answer in the choices.
How much is the amount of chemical undissolved after two hours in kg?Whatt is the particular solution to te DE?
Step by step
Solved in 2 steps
