The rate at which a certain drug is eliminated by the body follows first-order kinetics, with a half life of 68 minutes. Suppose in a particular patient the concentration of this drug in the bloodstream immediately after injection is 0.37 ug/mL. What will the concentration be 272 minutes later? Round your answer to 2 significant digits. mL O

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### Drug Elimination First-Order Kinetics Problem

The rate at which a certain drug is eliminated by the body follows first-order kinetics, with a half-life of 68 minutes.

**Problem Statement:**

Suppose in a particular patient the concentration of this drug in the bloodstream immediately after injection is 0.37 µg/mL. What will the concentration be 272 minutes later?

**Instructions:**

Round your answer to 2 significant digits.

**Text Box for Input:**

There is a text box where you need to input your answer in µg/mL.

**Buttons Available:**

1. **Checkmark (√)**: Likely used to submit the answer.
2. **Reset (↻)**: Likely used to clear the input and reset the problem.
3. **Question Mark (?)**: Likely provides help or hints related to solving the problem.

If you need to solve the problem, use the first-order decay formula:

\[ C(t) = C_0 \times \left(\frac{1}{2}\right)^{\frac{t}{t_{1/2}}} \]

Where:
- \( C(t) \) is the concentration at time \( t \)
- \( C_0 \) is the initial concentration
- \( t_{1/2} \) is the half-life
- \( t \) is the time elapsed

Given:
- \( C_0 = 0.37 \, \mu g/mL \)
- \( t_{1/2} = 68 \, \text{minutes} \)
- \( t = 272 \, \text{minutes} \)

By applying the formula, you can calculate the concentration 272 minutes later.
Transcribed Image Text:### Drug Elimination First-Order Kinetics Problem The rate at which a certain drug is eliminated by the body follows first-order kinetics, with a half-life of 68 minutes. **Problem Statement:** Suppose in a particular patient the concentration of this drug in the bloodstream immediately after injection is 0.37 µg/mL. What will the concentration be 272 minutes later? **Instructions:** Round your answer to 2 significant digits. **Text Box for Input:** There is a text box where you need to input your answer in µg/mL. **Buttons Available:** 1. **Checkmark (√)**: Likely used to submit the answer. 2. **Reset (↻)**: Likely used to clear the input and reset the problem. 3. **Question Mark (?)**: Likely provides help or hints related to solving the problem. If you need to solve the problem, use the first-order decay formula: \[ C(t) = C_0 \times \left(\frac{1}{2}\right)^{\frac{t}{t_{1/2}}} \] Where: - \( C(t) \) is the concentration at time \( t \) - \( C_0 \) is the initial concentration - \( t_{1/2} \) is the half-life - \( t \) is the time elapsed Given: - \( C_0 = 0.37 \, \mu g/mL \) - \( t_{1/2} = 68 \, \text{minutes} \) - \( t = 272 \, \text{minutes} \) By applying the formula, you can calculate the concentration 272 minutes later.
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