The random variable X has a probability density function given by: Ske-x, (o, 0s xs1; f(x) = otherwise. Then k is equal to: k = The above None of these k = k=e e4-1 The above The above
The random variable X has a probability density function given by: Ske-x, (o, 0s xs1; f(x) = otherwise. Then k is equal to: k = The above None of these k = k=e e4-1 The above The above
A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
Section: Chapter Questions
Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
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![The random variable X has a probability density function given by:
\[
f(x) =
\begin{cases}
ke^{-x}, & 0 \leq x \leq 1; \\
0, & \text{otherwise}.
\end{cases}
\]
Then \( k \) is equal to:
1. \( k = \frac{e^2}{e^2 - 1} \)
- Option: The above
2. (No option provided; placeholder remains blank)
- Option: None of these
3. \( k = \frac{e}{e - 1} \)
- Option: The above
4. \( k = \frac{e}{e^4 - 1} \)
- Option: The above
Each option is followed by a radio button with the text "The above" or "None of these" to select the correct answer.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fa9a59ff3-32cb-4a72-806c-172db4d1cb49%2F8a7bda21-91db-4e0e-9931-04293f96ca2d%2F8pckl7_processed.png&w=3840&q=75)
Transcribed Image Text:The random variable X has a probability density function given by:
\[
f(x) =
\begin{cases}
ke^{-x}, & 0 \leq x \leq 1; \\
0, & \text{otherwise}.
\end{cases}
\]
Then \( k \) is equal to:
1. \( k = \frac{e^2}{e^2 - 1} \)
- Option: The above
2. (No option provided; placeholder remains blank)
- Option: None of these
3. \( k = \frac{e}{e - 1} \)
- Option: The above
4. \( k = \frac{e}{e^4 - 1} \)
- Option: The above
Each option is followed by a radio button with the text "The above" or "None of these" to select the correct answer.
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