The random-number generator on calculators randomly generates a number between 0 and 1. The random variable X, the number generated, follows a uniform probability distribution.(a) Identify the graph of the uniform density function.(b) What is the probability of generating a number between 0.28 and 0.7?(c) What is the probability of generating a number greater than 0.83?(a) Choose the correct graph of the uniform density function below.A.1.21-0.8-0.6-0.4-0.2-Density0-0 0.2 0.4 0.6 0.8 1 1.2(b) The probability is(c) The probability is(Simplify your answer.)(Simplify your answer.)B.1.2-1-0.8-0.6-0.440.2-0+0Density0.2 0.4 0.6 0.8 1X1.2✔O C.1.2-10.8-0.6-0.4-0.2-0Density0.2 0.4 0.6 0.81X1.2

Given that,The random variable follows a uniform probability distribution. A random number…

Answered: The random-number generator on…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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In the probability distribution to the right, the random variable represents the number of hits a baseball player obtained in a game over the course of a season. Complete parts (a) through (f) below. P(x) O 0.1666 1 0.3347 0.2857 0.1495 3 0.0383 5 0.0252 u nua Describe the shape of the distribution. The distribution has one mode and is skewed right. (c) Compute and interpret the mean of the random variable X. Hx= 1.6338 hits (Type an integer or a decimal. Do not round.) Which of the following interpretations of the mean is correct? O A. The observed number of hits per game will be less than the mean number of hits per game for most games. Over the course of many games, one would expect the mean number of hits per game to be the mean of the random variable. O C. The observed number of hits per game will be equal to the mean number of hits per game for most games. O D. In any number of games, one would expect the mean number of hits per game to be the mean of the random variable. (d)…
The table below represents the probability density function for the random variable X. Find the standard deviation of X Round the final answer to two decimal places. 1/5 2/5 2/5 4 8 O Help copy to ClipboardDownload cSV
The random variable X has the distribution shown in the table to the right. P(X = x) (a) Find P(X= 3). (b) Find u. 0.3 0.2 4 (c) Find o?. 0.2 (a) Find P(X= 3). P(X = 3) =(Type an integer or a decimal.) (b) Find µ. H= (Type an integer or a decimal.) %3D (c) Find o?. o2 = (Type an integer or a decimal.)
Example 2 Il the probability density function of the random variable is f(x) = 1-x, x<1 , otherwis then what is the variance of X? M IMIE
Suppose the probability density function for a uniform distribution ranging from 0 to 1. Thus the probability that the random variable X is between 0.20 to 0.70 is
Because all airline passengers do not show up for their reserved sear an airline sells n=125 tickets for a flight that holds only 120 passengers. The probability that a passenger does not show up is 0.10 assume that the passengers behave independently.
A probability function for a discrete random variable, Y, is shown below. y P(Y=y) 4 0.4 6 0.2 8 0.2 10 0.2 Show how you would calculate the mean of Y. (You do NOT need to work this out). μ=
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The joint probability distribution of the number X of cars and the number Y of buses per signal cycle at a proposed left-turn lane is displayed in the accompanying joint probability table. P(x, y) 1 2 0.015 0.010 0.025 1 0.030 0.020 0.050 2 0.075 0.050 0.125 3 0.090 0.060 0.150 0.060 0.040 0.100 0.030 0.020 0.050 What is the probability that there is exactly one car and exactly one bus during a cycle? What is the probability that there is at most one car and at most one bus during a cycle? What is the probability that there is exactly one car during a cycle? Exactly one bus? P(exactly one car) = P(exactly one bus) = - Suppose the left-turn lane is to have a capacity of five cars and one bus is equivalent to three cars. What is the probability of an overflov during a cycle?
The probability density of a random variable X is given in the figure below. 0 1 X 2 From this density, the probability that X is at least 1.48 is: Give your answer to at least 4 decimal places.
(a) Formulate a probability statement to determine the value of z so that the area under the standard normal curve in the right tail is 0.0330: P(Za) 0.0330 (b) Convert the probability statement relating to an area to the left of the normal curve: (c) Locate the closest probability value available in the standard normal table. Give the answer with four decimal places. The closest probability value i (d) Find the z value corresponding to the answer for (c). Give the answer with two decimal places. Z= P(Zsa)-0.967
The probability density of a random variable X is given in the figure below. 1 From this density, the probability that X is at least 0.66 is:

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