The radius of the roll of paper shown in Figure is 7.7 cm and its moment of inertia is I = 3.3 x 10 -3 kg.m 2. A force of 2.5 N is exerted on the end of the roll for 1.3 s, but the paper does not tear so it begins to unroll. A constant friction torque of 0.11 m.N is exerted on the roll which gradually brings it to a stop. Assuming that the paper’s thickness is negligible, calculate the length of paper that unrolls during the time that the force is applied (1.3 s). (Your result must be in meters and include 2 digit after the decimal point. Maximum of 5% of error is accepted in your answer.)

The radius of the roll of paper shown in Figure is 7.7 cm and its moment of inertia is I = 3.3 x 10 -3 kg.m 2. A force of 2.5 N is exerted on the end of the roll for 1.3 s, but the paper does not tear so it begins to unroll. A constant friction torque of 0.11 m.N is exerted on the roll which gradually brings it to a stop. Assuming that the paper’s thickness is negligible, calculate the length of paper that unrolls during the time that the force is applied (1.3 s). (Your result must be in meters and include 2 digit after the decimal point. Maximum of 5% of error is accepted in your answer.)

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Question

The radius of the roll of paper shown in Figure is 7.7 cm and its moment of inertia is I = 3.3 x 10^-3 kg.m². A force of 2.5 N is exerted on the end of the roll for 1.3 s, but the paper does not tear so it begins to unroll. A constant friction torque of 0.11 m.N is exerted on the roll which gradually brings it to a stop. Assuming that the paper’s thickness is negligible, calculate the length of paper that unrolls during the time that the force is applied (1.3 s). (Your result must be in meters and include 2 digit after the decimal point. Maximum of 5% of error is accepted in your answer.)