1. A solid cylinder of mass M=3.0 kg and radius R= 5.0 cm is rolling without slipping on a horizontal plane with a speed v = 5.0 m/s when it reaches an inclined plane of inclination 0 = What maximum height along the inclined plane the cylinder will reach before stopping? ( Moment of inertia of cylinder I= (1/2) MR² ).

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1.
A solid cylinder of mass M=3.0 kg and radius R= 5.0 cm is rolling without slipping on a horizontal
30°.
plane with a speed v = 5.0 m/s when it reaches an inclined plane of inclination 0 =
What maximum height along the inclined plane the cylinder will reach before stopping?
MR² ).
( Moment of inertia of cylinder I=
= (1/2) N
Use Law of conservation of energy.
A bullet of mass m=2.00g is moving horizontally with a speed
of 500.0m/s.. The bullet strikes and becomes embedded in the edge of a solid disk of
mass M=3.20kg and radius R=0.500m.. The cylinder is free to rotate around its axis and is
initially at rest.
What is the angular velocity of the disk immediately after the bullet is embedded?
2.
Moment of inertia of cylinder I= (1/2) MR² .
Transcribed Image Text:1. A solid cylinder of mass M=3.0 kg and radius R= 5.0 cm is rolling without slipping on a horizontal 30°. plane with a speed v = 5.0 m/s when it reaches an inclined plane of inclination 0 = What maximum height along the inclined plane the cylinder will reach before stopping? MR² ). ( Moment of inertia of cylinder I= = (1/2) N Use Law of conservation of energy. A bullet of mass m=2.00g is moving horizontally with a speed of 500.0m/s.. The bullet strikes and becomes embedded in the edge of a solid disk of mass M=3.20kg and radius R=0.500m.. The cylinder is free to rotate around its axis and is initially at rest. What is the angular velocity of the disk immediately after the bullet is embedded? 2. Moment of inertia of cylinder I= (1/2) MR² .
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