The radionuclide Tc-99m is a gamma photon emitter. The emitted gamma photon energy is 141 keV. The scintillation crystal in a Gamma camera will convert the single gamma photon to a burst of visible photons. Assuming the generated visible photons wavelength is 550 nm, calculate how many visible 550-nm photons will have the same amount of energy as a single 141-keV gamma photon?
Nuclear Fission
Nuclear fission is a type of nuclear reaction in which heavier nuclei split into lighter nuclei by releasing a large quantity of energy. The elements like uranium-235 and plutonium-239 isotope undergo nuclear fission releasing energy. When nuclei undergo fission, some quantity of mass is lost. The lost mass is converted to nuclear energy. Nuclear fission reaction is used in nuclear power plants and atomic bombs. In nuclear power plants, nuclear reactors are used to generate electricity.
Endothermic Nuclear Reaction
A nuclear reaction can be described as a process where two atoms, or two nuclei or nucleus and subatomic particles such as a proton, neutron interact together, and a large amount of energy is produced and new elements are also produced.
Question: The radionuclide Tc-99m is a gamma photon emitter. The emitted gamma photon
energy is 141 keV. The scintillation crystal in a Gamma camera will convert the single gamma
photon to a burst of visible photons. Assuming the generated visible photons wavelength is 550
nm, calculate how many visible 550-nm photons will have the same amount of energy as a single
141-keV gamma photon?
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