Compare the wavelength of 1.0-MeV gamma-ray photon with that of a neutron having the mc²939 MeV) same kinetic energy. (for a neutron,
Compare the wavelength of 1.0-MeV gamma-ray photon with that of a neutron having the mc²939 MeV) same kinetic energy. (for a neutron,
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![**Problem Statement:**
Compare the wavelength of a 1.0-MeV gamma-ray photon with that of a neutron having the same kinetic energy. (For a neutron, \( mc^2 = 939 \, \text{MeV} \)).
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**Explanation:**
This problem involves comparing the wavelengths of two different particles, a gamma-ray photon and a neutron, when both have the same kinetic energy of 1.0 MeV.
- **Gamma-Ray Photon:**
- Energy of photon (\(E\)) = 1.0 MeV.
- Use the equation: \( \lambda = \frac{hc}{E} \) to calculate the wavelength (\(\lambda\)), where \(h\) is Planck's constant and \(c\) is the speed of light.
- **Neutron:**
- Kinetic energy = 1.0 MeV.
- Use the kinetic energy and rest energy (\(mc^2\)) to find the momentum (\(p\)) and then calculate the wavelength using: \( \lambda = \frac{h}{p} \).
This requires knowledge of energy-momentum relationships in quantum mechanics and relativistic physics.
No graphs or diagrams are included in the text.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F5b55a0fb-5dff-4587-97c0-c3ec381e9c7e%2Ff8d3b94a-84f0-4225-acd0-9de99799ec79%2Fsmi26vi_processed.png&w=3840&q=75)
Transcribed Image Text:**Problem Statement:**
Compare the wavelength of a 1.0-MeV gamma-ray photon with that of a neutron having the same kinetic energy. (For a neutron, \( mc^2 = 939 \, \text{MeV} \)).
---
**Explanation:**
This problem involves comparing the wavelengths of two different particles, a gamma-ray photon and a neutron, when both have the same kinetic energy of 1.0 MeV.
- **Gamma-Ray Photon:**
- Energy of photon (\(E\)) = 1.0 MeV.
- Use the equation: \( \lambda = \frac{hc}{E} \) to calculate the wavelength (\(\lambda\)), where \(h\) is Planck's constant and \(c\) is the speed of light.
- **Neutron:**
- Kinetic energy = 1.0 MeV.
- Use the kinetic energy and rest energy (\(mc^2\)) to find the momentum (\(p\)) and then calculate the wavelength using: \( \lambda = \frac{h}{p} \).
This requires knowledge of energy-momentum relationships in quantum mechanics and relativistic physics.
No graphs or diagrams are included in the text.
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