The radical chain begins (initiation) with the photochemical cleavage of a Br-Br bond, affording two bromine atoms (Br ): Br-Br Br + Then, the propagation steps take place. First, the bromine atom reacts with the substrate to afford a resonance-stabilized benzylic radical. Represent this process and the different resonance forms of the resulting radical: СООН Br HBr + > H.
The radical chain begins (initiation) with the photochemical cleavage of a Br-Br bond, affording two bromine atoms (Br ): Br-Br Br + Then, the propagation steps take place. First, the bromine atom reacts with the substrate to afford a resonance-stabilized benzylic radical. Represent this process and the different resonance forms of the resulting radical: СООН Br HBr + > H.
Chapter10: Organohalides
Section10.SE: Something Extra
Problem 21MP: Alkyl halides can be reduced to alkanes by a radical reaction with tributyltin hydride, (C4H9)3SnH,...
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Transcribed Image Text:omplete the following mechanistic steps (#1 through 4) representing every step of the
echanism:
The radical chain begins (initiation) with the photochemical cleavage of a Br-Br bond, affording
two bromine atoms (Br ):
Br-Br
Br
Then, the propagation steps take place. First, the bromine atom reacts with the substrate to
afford a resonance-stabilized benzylic radical. Represent this process and the different
resonance forms of the resulting radical:
СООН
+ Br
HBr +
Expert Solution

Step 1
Redical chain begins with Br2 in photochemical condition .
Reaction proceed through Radical mechanism
Complete resonating structure is given below in next step
Step by step
Solved in 2 steps with 1 images

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