The quantity of charge Q in coulombs (C) that has passed through a point in a wire up to time t (measured in seconds) is given by Q(t) = t³ — 4t² + 7t + 4. (a) Find the current when t = 0.7 s. (b) Find the current when t = 1 s. At what time is the current the lowest? t =

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Chapter1: Units, Trigonometry. And Vectors
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The quantity of charge \( Q \) in coulombs (C) that has passed through a point in a wire up to time \( t \) (measured in seconds) is given by  

\[ Q(t) = t^3 - 4t^2 + 7t + 4. \]

(a) Find the current when \( t = 0.7 \, \text{s} \).  
\[
\boxed{\phantom{5}}
\] A

(b) Find the current when \( t = 1 \, \text{s} \).  
\[
\boxed{\phantom{5}}
\] A

At what time is the current the lowest?  
\( t = \boxed{\phantom{5}} \) s
Transcribed Image Text:The quantity of charge \( Q \) in coulombs (C) that has passed through a point in a wire up to time \( t \) (measured in seconds) is given by \[ Q(t) = t^3 - 4t^2 + 7t + 4. \] (a) Find the current when \( t = 0.7 \, \text{s} \). \[ \boxed{\phantom{5}} \] A (b) Find the current when \( t = 1 \, \text{s} \). \[ \boxed{\phantom{5}} \] A At what time is the current the lowest? \( t = \boxed{\phantom{5}} \) s
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