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The pump has to draw 0.7 m³/s flow to the pipe at an elevation of 10 m where a pressure p = -88.29 kPa gage prevails. A head loss h = 0.5 V²/2g assumed, where V is the velocity in the discharge pipe. If the pump efficiency is 70%, how much power has to be drawn from the national gridline? p= -88.20 KPa gage Elevation = 10 m- D= 30 cm - Elevation =6 m 40 cm diameter Water T= 10-C Elevation = 2 m O Pp = 24.52 kW O Pp = 83.39 kW O Pp = 63.77 kW All other answers are wrong

The pump has to draw 0.7 m³/s flow to the pipe at an elevation of 10 m where a pressure p = -88.29 kPa gage prevails. A head loss h = 0.5 V²/2g assumed, where V is the velocity in the discharge pipe. If the pump efficiency is 70%, how much power has to be drawn from the national gridline? p= -88.20 KPa gage Elevation = 10 m- D= 30 cm - Elevation =6 m 40 cm diameter Water T= 10-C Elevation = 2 m O Pp = 24.52 kW O Pp = 83.39 kW O Pp = 63.77 kW All other answers are wrong

Structural Analysis
Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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The pump has to draw 0.7 m/s flow to the pipe at an elevation of 10 m where a pressurep = -88.29 kPa gage prevails. A head loss h̟ = 0.5 V²/2g assumed, where V is the velocity in the discharge pipe. If the pump efficiency is 70%, how much power has to be drawn from the national gridline? p=-88.20 KPa gage Elevation = 10 m - D= 30 cm Elevation = 6 m 40 cm diameter Water T= 10-C Elevation = 2 m O P, = 24.52 kW O Pp = 83.39 kW O Pp = 63.77 kW O All other answers are wrong
Transcribed Image Text:The pump has to draw 0.7 m/s flow to the pipe at an elevation of 10 m where a pressurep = -88.29 kPa gage prevails. A head loss h̟ = 0.5 V²/2g assumed, where V is the velocity in the discharge pipe. If the pump efficiency is 70%, how much power has to be drawn from the national gridline? p=-88.20 KPa gage Elevation = 10 m - D= 30 cm Elevation = 6 m 40 cm diameter Water T= 10-C Elevation = 2 m O P, = 24.52 kW O Pp = 83.39 kW O Pp = 63.77 kW O All other answers are wrong
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