The proper operation of typical home appliances requires voltage levels that do not vary much. Listed below are 11 voltage levels (in volts) at a random house on 11 different days. 120 119.9 119.9 120 119.8 120 119.9 120.1 120.5 119.9 120.3 The mean of the data set is 120; the sample standard deviation is 0.21; if the normality plot is not provided you may assume that the voltages are normally distributed. Use the given sample standard deviation for your work. a. Construct a 90% confidence interval for the variance (standard deviation) of all voltages in the house. i. Procedure: Select an answer ii. Assumptions: (select everything that applies) Sample size is greater than 30 Population standard deviation is unknown Simple random sample Normal population Population standard deviation is known The number of positive and negative responses are both greater than 10 iii. Unknown parameter: Select an answer O iv. Point estimate: Select an answer (Round the answer to 4 decimal places) α v. Confidence level %→α= α and 1 2 Critical values: right= left= (Round

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The proper operation of typical home appliances requires
voltage levels that do not vary much. Listed below are 11
voltage levels (in volts) at a random house on 11 different
days.
120 119.9 119.9
120 119.8
120
119.9
120.1 120.5 119.9
120.3
The mean of the data set is 120; the sample standard
deviation is 0.21; if the normality plot is not provided you
may assume that the voltages are normally distributed. Use
the given sample standard deviation for your work.
a. Construct a 90% confidence interval for the variance
(standard deviation) of all voltages in the house.
i. Procedure: Select an answer
ii. Assumptions: (select everything that applies)
Sample size is greater than 30
Population standard deviation is unknown
Simple random sample
Normal population
Population standard deviation is known
The number of positive and negative
responses are both greater than 10
iii. Unknown parameter: Select an answer
iv. Point estimate: Select an answer î
(Round the answer to 4 decimal places)
v. Confidence level %→α =
α
and 1
2
Critical values: right=
left=
(>
||
(Round
Transcribed Image Text:The proper operation of typical home appliances requires voltage levels that do not vary much. Listed below are 11 voltage levels (in volts) at a random house on 11 different days. 120 119.9 119.9 120 119.8 120 119.9 120.1 120.5 119.9 120.3 The mean of the data set is 120; the sample standard deviation is 0.21; if the normality plot is not provided you may assume that the voltages are normally distributed. Use the given sample standard deviation for your work. a. Construct a 90% confidence interval for the variance (standard deviation) of all voltages in the house. i. Procedure: Select an answer ii. Assumptions: (select everything that applies) Sample size is greater than 30 Population standard deviation is unknown Simple random sample Normal population Population standard deviation is known The number of positive and negative responses are both greater than 10 iii. Unknown parameter: Select an answer iv. Point estimate: Select an answer î (Round the answer to 4 decimal places) v. Confidence level %→α = α and 1 2 Critical values: right= left= (> || (Round
the answer to 3 decimal places)
vi. Margin of error (if applicable):
answer to 4 decimal places)
vii. Lower bound:
viii. Upper bound:
decimal places)
ix. Confidence interval:(
x.
Interpretation: We are 0⁹
% confident that the
and
true population parameter is between
b. Based on the confidence interval, is it reasonable to
believe that the population variance is less than 0.02?
Explain.
because Select an answer
0.02.
"
decimal places)
(Round the
(Round the answer to 4
(Round the answer to 4
Transcribed Image Text:the answer to 3 decimal places) vi. Margin of error (if applicable): answer to 4 decimal places) vii. Lower bound: viii. Upper bound: decimal places) ix. Confidence interval:( x. Interpretation: We are 0⁹ % confident that the and true population parameter is between b. Based on the confidence interval, is it reasonable to believe that the population variance is less than 0.02? Explain. because Select an answer 0.02. " decimal places) (Round the (Round the answer to 4 (Round the answer to 4
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