The products of the following reaction are: CH;CH, C-0-CH,CH; + NAOH CH;CH,C-O Na* + CH;CH,OH CH;CH,C-OH + CH,CH,OH CH;CH, C-OH + CH;CH,O Na* CH,CH, C-O' Na* + CH,CH,0 Na*
The products of the following reaction are: CH;CH, C-0-CH,CH; + NAOH CH;CH,C-O Na* + CH;CH,OH CH;CH,C-OH + CH,CH,OH CH;CH, C-OH + CH;CH,O Na* CH,CH, C-O' Na* + CH,CH,0 Na*
Chemistry: The Molecular Science
5th Edition
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:John W. Moore, Conrad L. Stanitski
Chapter10: Fuels, Organic Chemicals, And Polymers
Section: Chapter Questions
Problem 121QRT
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![### Understanding Reaction Products - Educational Guide
#### Given Reaction:
The products of the following reaction are:
\[ \text{CH}_3\text{CH}_2\text{C} \doteq CO \cdot \text{O-CH}_2\text{CH}_3 + \text{NaOH} \rightarrow \]
#### Choices:
1. \( \text{CH}_3\text{CH}_2\text{C} \dot{=}{\displaystyle CO^- \cdot \text{Na}^+} + \text{CH}_3\text{CH}_2\text{OH} \)
2. \( \text{CH}_3\text{CH}_2\text{C} \dot{=}{\displaystyle COH} + \text{CH}_3\text{CH}_2\text{OH} \)
3. \( \text{CH}_3\text{CH}_2\text{C} \dot{=}{\displaystyle COH} + \text{H}_3\text{C-CH}_2\text{O}^-\text{Na}^+ \)
4. \( \text{CH}_3\text{CH}_2\text{C} \dot{=}{\displaystyle CO^- \cdot \text{Na}^+} + \text{CH}_3\text{CH}_2\text{O}^- \text{Na}^+ \)
#### Detailed Explanation:
The reaction in question is an example of a nucleophilic acyl substitution where an ester reacts with a strong base, in this case, NaOH, through a process known as saponification.
- **Saponification:** This is the hydrolysis of an ester under basic conditions to produce a carboxylate salt and an alcohol.
For the provided reaction:
\[ \text{CH}_3\text{CH}_2\text{C} \doteq CO \cdot \text{O-CH}_2\text{CH}_3 + \text{NaOH} \rightarrow \]
- The NaOH disassociates into Na+ and OH- ions.
- The OH- ion acts as a nucleophile and attacks the carbonyl carbon (C=O) of the ester, breaking the ester bond.
- This results in the formation](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fccbc8bf4-8e89-4e4e-b9a4-2700c1ba500b%2Fceb59487-476a-448b-bfe8-e529337cacf0%2Fp0chd28_processed.png&w=3840&q=75)
Transcribed Image Text:### Understanding Reaction Products - Educational Guide
#### Given Reaction:
The products of the following reaction are:
\[ \text{CH}_3\text{CH}_2\text{C} \doteq CO \cdot \text{O-CH}_2\text{CH}_3 + \text{NaOH} \rightarrow \]
#### Choices:
1. \( \text{CH}_3\text{CH}_2\text{C} \dot{=}{\displaystyle CO^- \cdot \text{Na}^+} + \text{CH}_3\text{CH}_2\text{OH} \)
2. \( \text{CH}_3\text{CH}_2\text{C} \dot{=}{\displaystyle COH} + \text{CH}_3\text{CH}_2\text{OH} \)
3. \( \text{CH}_3\text{CH}_2\text{C} \dot{=}{\displaystyle COH} + \text{H}_3\text{C-CH}_2\text{O}^-\text{Na}^+ \)
4. \( \text{CH}_3\text{CH}_2\text{C} \dot{=}{\displaystyle CO^- \cdot \text{Na}^+} + \text{CH}_3\text{CH}_2\text{O}^- \text{Na}^+ \)
#### Detailed Explanation:
The reaction in question is an example of a nucleophilic acyl substitution where an ester reacts with a strong base, in this case, NaOH, through a process known as saponification.
- **Saponification:** This is the hydrolysis of an ester under basic conditions to produce a carboxylate salt and an alcohol.
For the provided reaction:
\[ \text{CH}_3\text{CH}_2\text{C} \doteq CO \cdot \text{O-CH}_2\text{CH}_3 + \text{NaOH} \rightarrow \]
- The NaOH disassociates into Na+ and OH- ions.
- The OH- ion acts as a nucleophile and attacks the carbonyl carbon (C=O) of the ester, breaking the ester bond.
- This results in the formation
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