the problems. O Kendra is filling cone-shaped baskets, each with a height of 20 inches and radius of 6 inches, to use as table decorations. Part A In terms of T, what is the exact volume of each cone-shaped basket? Answer: cubic inches Part B Kendra says that if she doubles the radius from 6 inches to 12 inches, the cone will have double the volume. Is she correct? Why or why not? A Yes, doubling the radius results in a volume that is twice as great as the original volume. B No, the radius is 6 inches longer, so the new cone will have a volume that is 6 more than the original volume. 1 C No, one factor of the formula for a cone is -, so the new cone will have a volume x2 =of the original volume. D No, the radius is squared and all the other numbers in the formula are the same, so because 12² = 144 and 6² = 36, the new cone will have a volume that is four times the original volume. %3D %3D
the problems. O Kendra is filling cone-shaped baskets, each with a height of 20 inches and radius of 6 inches, to use as table decorations. Part A In terms of T, what is the exact volume of each cone-shaped basket? Answer: cubic inches Part B Kendra says that if she doubles the radius from 6 inches to 12 inches, the cone will have double the volume. Is she correct? Why or why not? A Yes, doubling the radius results in a volume that is twice as great as the original volume. B No, the radius is 6 inches longer, so the new cone will have a volume that is 6 more than the original volume. 1 C No, one factor of the formula for a cone is -, so the new cone will have a volume x2 =of the original volume. D No, the radius is squared and all the other numbers in the formula are the same, so because 12² = 144 and 6² = 36, the new cone will have a volume that is four times the original volume. %3D %3D
Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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
Transcribed Image Text:Destiny
Name
Pize
Ready Mathematics
Date
Lesson 27 Quiz
Solve the problems.
1 Kendra is filling cone-shaped baskets, each with a height of 20 inches and radius of
6 inches, to use as table decorations.
Part A
In terms of , what is the exact volume of each cone-shaped basket?
Answer:
cubic inches
Part B
Kendra says that if she doubles the radius from 6 inches to 12 inches, the cone will
have double the volume. Is she correct? Why or why not?
Yes, doubling the radius results in a volume that is twice as great as the original
volume.
A
B No, the radius is 6 inches longer, so the new cone will have a volume that iS
6 more than the original volume.
SO
C No, one factor of the formula for a cone is -, so the new cone will have a volume
D No, the radius is squared and all the other numbers in the formula are the same,
so because 12² = 144 and 6² = 36, the new cone will have a volume that is four
times the original volume.
X 2 =of the original volume.
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