The probability of a molecule of mass (m) in a gas at temp (7) having a speed of (c) is given by: 3/2 p = c² x (m²) ² x exp Where k is the Boltzmann constant. Show that the maximum probability is found when: C = 2kT m mc² 2kT
The probability of a molecule of mass (m) in a gas at temp (7) having a speed of (c) is given by: 3/2 p = c² x (m²) ² x exp Where k is the Boltzmann constant. Show that the maximum probability is found when: C = 2kT m mc² 2kT
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by:
p = c² x
3/2
P(-2160
Where k is the Boltzmann constant. Show that the maximum probability is found when:
m
(27KT)
2лkТ
C =
2kT
m
mc²
2kT
x exp"
Transcribed Image Text:The probability of a molecule of mass (m) in a gas at temp (7) having a speed of (c) is given
by:
p = c² x
3/2
P(-2160
Where k is the Boltzmann constant. Show that the maximum probability is found when:
m
(27KT)
2лkТ
C =
2kT
m
mc²
2kT
x exp
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