**Problem Description: Equilibrium of Aqueous Solutions**The preparations of two aqueous solutions are described in the table below. For each solution, write the chemical formulas of the major species present at equilibrium. You can leave out water itself.Write the chemical formulas of the species that will act as acids in the 'acids' row, the formulas of the species that will act as bases in the 'bases' row, and the formulas of the species that will act as neither acids nor bases in the 'other' row.*It is helpful to keep in mind that NH₃ is a weak base.***Solution 1:**- **Description:** 1.2 mol of HBr is added to 1.0 L of a 1.2 M NH₃ solution.- **Equilibrium Species:** - **Acids:** - **Bases:** - **Other:****Solution 2:**- **Description:** 0.1 mol of NaOH is added to 1.0 L of a solution that is 0.4 M in both NH₃ and NH₄Br.- **Equilibrium Species:** - **Acids:** - **Bases:** - **Other:****Task:** Fill in the appropriate chemical formulas for acids, bases, and other species in the spaces provided.**Instructions:**- **Continue:** Proceed to the next question or task.- **Save For Later:** Save your progress for completion at a later time.- **Submit Assignment:** Submit the completed task for evaluation.**Accessibility Options:** Terms of Use, Privacy Center, Accessibility.

Answer:When acid and base solutions are mixed, they react vigorously and form salt and water. It is a very fast, irreversible reaction, therefore it reaches completion until one of the reactants gets consumed completely.Since, NH3 is a base and HBr is an acid, therefore when HBr is added in the solution of ammonia acid-base reaction will take place as shown below:Since, HBr and NH3 has equal number of moles, complete neutralization of NH3 takes place and solution is only going to have solution and is the conjugate acid of weak base NH3, so, after the reaction, species present in solution are:Br- is the anion of strong acid HBr, therefore it will act like a neutral specie and is the conjugate acid of weak base NH3, therefore it will act like an acid.Since, NaOH is a base and is a weak acid, therefore when NaOH is added in the solution of , acid-base reaction will take place as shown below:Since, NaOH has lesser number of moles, therefore it will be the limiting reagent and gets consumed in the reaction completely, therefore after the addition of NaOH, 4 species are present in the solution as shown below:Br- is the anion of strong acid HBr and Na+ is the cation of strong base NaOH, therefore they will act like a neutral specie and is the conjugate acid of weak base NH3, therefore it will act like an acid.Answer-1Answer-2

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The preparations of two aqueous solutions are described in the table below. For each solution, write the chemical formulas of the major species present at equilibrium. You can leave out water itself. Write the chemical formulas of the species that will act as acids in the 'acids' row, the formulas of the species that will act as bases in the 'bases' row, and the formulas of the species that will act as neither acids nor bases in the 'other' row. You will find it useful to keep in mind that NH, is a weak base. 1.2 mol of HBr is added to 1.0 L of a 1.2 M NH3 solution. 0,1 mol of NaOH is added to 1.0 L of a solution that is 0.4M in both NH₂ and NH Br. 0 0 0 0 0 0 acids: bases: other: acids: bases: 0 other: D X On 0.0....

The preparations of two aqueous solutions are described in the table below. For each solution, write the chemical formulas of the major species present at equilibrium. You can leave out water itself. Write the chemical formulas of the species that will act as acids in the 'acids' row, the formulas of the species that will act as bases in the 'bases' row, and the formulas of the species that will act as neither acids nor bases in the 'other' row. You will find it useful to keep in mind that NH, is a weak base. 1.2 mol of HBr is added to 1.0 L of a 1.2 M NH3 solution. 0,1 mol of NaOH is added to 1.0 L of a solution that is 0.4M in both NH₂ and NH Br. 0 0 0 0 0 0 acids: bases: other: acids: bases: 0 other: D X On 0.0....

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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