The potential of a voltaic cell is 0.698 V in which the followingreaction takes place:2NO, (aq) + 3H2(g)→2NO(g) + 2OH¯(aq) + 2H,OConsidering the voltaic cell is under the following conditions: [NO3]= 0.0315 M, PNO = 0.922 atm, PH2 = 0.437 atm. Determine the pOH ofthe reaction.Answer:

Given data, EMF = 0.698V [NO3-] = 0.0315M PNO = 0.922atm PH2 = 0.437atm

The potential of a voltaic cell is 0.698 V in which the following reaction takes place: 2NO, (aq) + 3H2(g) → 2NO(g) + 20H¯(aq) + 2H2O Considering the voltaic cell is under the following conditions: [NO3] = 0.0315 M, PNO = 0.922 atm, PH2 = 0.437 atm. Determine the pOH of the reaction.

The potential of a voltaic cell is 0.698 V in which the following reaction takes place: 2NO, (aq) + 3H2(g) → 2NO(g) + 20H¯(aq) + 2H2O Considering the voltaic cell is under the following conditions: [NO3] = 0.0315 M, PNO = 0.922 atm, PH2 = 0.437 atm. Determine the pOH of the reaction.

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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