The potential energy of one of the atoms in the hydrogen molecule is given by U(x) = U₁ (e-2(1-10)/b - 2e-(1-10)/b) where U₁ = 2.36 [eV], zo = 0.037 [nm], and b = 0.034 [nm]. Note that 1 [eV] = 1.6 × 10-¹⁹ [J]. Part (a) Find the energy of the hydrogen molecule in ground state. Part (b) If the measured energy of each atom in the hydrogen molecule is E= -1.15 [eV], where are the classical turning points of the atomic vibration in the hydrogen molecule?
The potential energy of one of the atoms in the hydrogen molecule is given by U(x) = U₁ (e-2(1-10)/b - 2e-(1-10)/b) where U₁ = 2.36 [eV], zo = 0.037 [nm], and b = 0.034 [nm]. Note that 1 [eV] = 1.6 × 10-¹⁹ [J]. Part (a) Find the energy of the hydrogen molecule in ground state. Part (b) If the measured energy of each atom in the hydrogen molecule is E= -1.15 [eV], where are the classical turning points of the atomic vibration in the hydrogen molecule?
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![The potential energy of one of the atoms in the hydrogen molecule is given by
U(x) = U₁ (e-2(1-10)/b - 2e-(1-10)/b)
where U₁ = 2.36 [eV], zo = 0.037 [nm], and b = 0.034 [nm]. Note that 1 [eV] = 1.6 × 10-¹⁹ [J].
Part (a) Find the energy of the hydrogen molecule in ground state.
Part (b) If the measured energy of each atom in the hydrogen molecule is E= -1.15 [eV], where are the
classical turning points of the atomic vibration in the hydrogen molecule?](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fa1d592a5-ec96-4b1d-bddf-23e27014debe%2F3dda9e01-5037-4833-80b6-c033fb3fb6de%2F2iqf8l_processed.png&w=3840&q=75)
Transcribed Image Text:The potential energy of one of the atoms in the hydrogen molecule is given by
U(x) = U₁ (e-2(1-10)/b - 2e-(1-10)/b)
where U₁ = 2.36 [eV], zo = 0.037 [nm], and b = 0.034 [nm]. Note that 1 [eV] = 1.6 × 10-¹⁹ [J].
Part (a) Find the energy of the hydrogen molecule in ground state.
Part (b) If the measured energy of each atom in the hydrogen molecule is E= -1.15 [eV], where are the
classical turning points of the atomic vibration in the hydrogen molecule?
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