The position of a vibrating spring after t seconds is given by f(t) = (1/2) cost − (1/5) sin t meters. Positive and negative values of f(t) mean that the spring is to the right and the left of its equilibrium position, respectively. Find the position, the velocity, and acceleration of the spring at t = 1.

College Algebra
10th Edition
ISBN:9781337282291
Author:Ron Larson
Publisher:Ron Larson
Chapter5: Exponential And Logarithmic Functions
Section: Chapter Questions
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The position of a vibrating spring after t seconds is given by f(t) = (1/2) cost − (1/5) sin t meters. Positive and negative values of f(t) mean that the spring is to the right and the left of its equilibrium position, respectively. Find the position, the velocity, and acceleration of the spring at t = 1.

Expert Solution
Step 1

The given position of a vibrating spring is ft=12cost-15sint, where t is the time in seconds.

Evaluate the position of the spring at t=1 as follows.

f1=12cos1-15sin1=120.5403-150.8414=0.27015-0.168280.102

Therefore, the position of the spring at t=1 is 0.102 m to the right of the equilibrium position.

Step 2

Evaluate the velocity of the spring as follows.

ddtft=ddt12cost-15sint=12-sint-15cost=-12sint-15cost

Evaluate the velocity at t=1 as follows.

v1=-12sin1-15cos1=-0.42073--0.10806-0.523

Therefore, the velocity of the spring at t=1 is -0.523 m/sec.

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