Plz solve the question using c programming without changing or adding any other library other than the library # include < stdio.h >, the second photo is a sample of how the coding should look like #include#includefloat f(float x);float df (float x):void newton (float x1, float tol, float* add_root, int" add_iter);int main(void) {float x1, tol, root;int iter;FILE" fout = fopen("rootsout.txt", "a");printf("Enter the starting guess and the desired tolerance: ");scanf("%f%f", 8x1, Stol);newton (x1, tol, Broot,&iter);fprintf(fout, "After %d iterations the estimated root near XF is: f\n", iter, x1, root);fclose(fout);return;float (float x){float yiy = sin(x)-2.0*exp(-x);return y;float df (float x){float yiy = cos(x)+2.€*exp(-x);return y;}}void newton (float x1, float tol, float" add_root, int* add_iter){float x2;int iter=;while(1){x2 = x1 *(x1)/df(x1);if (fabs (x2-x1) The polar coordinates r and 0 of a point (x, y) in the plane can be computed as follows:√x² + y²720-T=acos(x/r) if r> 0 and y > 0-acos(x/r) if r > 0 and y ≤ 00Write a program which uses a function called polar() to compute the polar coordinates ofa point. Your program must consist of a main program and a function called polar. Thefunction polar() takes the r and y coordinates of a point as arguments and computes thepolar coordinates (r, 0). The main program opens the output file polarout.txt for appending(mode "a"), reads the (x, y) coordinates from the keyboard, calls polar (), and then writesboth the (x, y) coordinates and the corresponding (7, 8) polar coordinates to the output file.The first (and subsequent) lines of your output should look like:The polar coordinates of (2.0000, 2.0000) are = 2.8284 and theta = 0.78541For marking purposes run your program 4 times with (x, y) as follows: (2,2), (1,-1),(0,1) and (3,-1).

Answered: The polar coordinates r and 9 of a…

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Plz solve the question using c programming without changing or adding any other library other than the library # include < stdio.h >, the second photo is a sample of how the coding should look like

#include<stdio.h>
#include<math.h>
float f(float x);
float df (float x):
void newton (float x1, float tol, float* add_root, int" add_iter);
int main(void) {
float x1, tol, root;
int iter;
FILE" fout = fopen("rootsout.txt", "a");
printf("Enter the starting guess and the desired tolerance: ");
scanf("%f%f", 8x1, Stol);
newton (x1, tol, Broot,&iter);
fprintf(fout, "After %d iterations the estimated root near XF is: f\n", iter, x1, root);
fclose(fout);
return;
float (float x){
float yi
y = sin(x)-2.0*exp(-x);
return y;
float df (float x){
float yi
y = cos(x)+2.€*exp(-x);
return y;
}
}
void newton (float x1, float tol, float" add_root, int* add_iter){
float x2;
int iter=;
while(1){
x2 = x1 *(x1)/df(x1);
if (fabs (x2-x1)<tol){
break;
}
x2=x2;
"add_root = x2;
add_iter = iter;
return;

The polar coordinates r and 0 of a point (x, y) in the plane can be computed as follows:
√x² + y²
72
0-
T=
acos(x/r) if r> 0 and y > 0
-acos(x/r) if r > 0 and y ≤ 0
0
Write a program which uses a function called polar() to compute the polar coordinates of
a point. Your program must consist of a main program and a function called polar. The
function polar() takes the r and y coordinates of a point as arguments and computes the
polar coordinates (r, 0). The main program opens the output file polarout.txt for appending
(mode "a"), reads the (x, y) coordinates from the keyboard, calls polar (), and then writes
both the (x, y) coordinates and the corresponding (7, 8) polar coordinates to the output file.
The first (and subsequent) lines of your output should look like:
The polar coordinates of (2.0000, 2.0000) are = 2.8284 and theta = 0.7854
1
For marking purposes run your program 4 times with (x, y) as follows: (2,2), (1,-1),
(0,1) and (3,-1).

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C Introduction:-

Dennis M. Ritchie created the imperative, procedural, general-purpose C language for the UNIX OS in 1972 while working at Bell Telephone. Along with Java, which is primarily utilised by contemporary programmers, the C language is currently one of the most popular computer languages.

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