The plant in the picture has a mass of 27 kg, and is hanging at a distance of 2.1 meters from the wall. The horizontal rod has a mass of 6.3 kg. Assume that its weight is evenly distributed, therefore it can be treated as a single force at the center of mass. The rod is 2.8 meters long, and there is a cable at a 27° angle supporting it at the end.**Objective:**Using the wall as the axis of rotation, find the magnitude of the downward torque, from both the weight of the rod and the weight of the plant.\[\tau = \_\_\_\_ \, \text{N} \cdot \text{m}\]The downward torque is balanced by the upward torque from the force of tension. Find the magnitude of the force of tension.\[T = \_\_\_\_ \, \text{N}\]\( F \) is the contact force between the rod and the wall. Using the other horizontal force in the problem, find the horizontal component of \( F \) (the normal force) that must be present for the rod to be at equilibrium.\[F_x = \_\_\_\_ \, \text{N}\]There is a vertical force from a component of the tension, but this is not enough to balance the downward forces. Find the vertical force that must be present for the wall to keep the rod up.\[F_y = \_\_\_\_ \, \text{N}\]**Diagram Explanation:**A diagram is likely illustrating a plant hanging on a rod supported by a cable, positioned at specific distances from a wall to demonstrate the mechanics of forces acting in equilibrium calculations. The image depicts a horizontal rod supported by a cable at an angle, with a plant hanging from the rod. The plant has a mass of 27 kg and is positioned 2.1 meters from the wall. The rod itself has a mass of 6.3 kg and a length of 2.8 meters. The rod’s weight is considered to be evenly distributed, acting as a single force at its center of mass. A cable, attached to the end of the rod, holds it at a 27° angle to the horizontal.The diagram includes:- A red tension force vector (T) at the angle, indicating the direction and support provided by the cable.- Blue components of force, labeled as \( F_x \) and \( F_y \), representing the horizontal and vertical components of the tension.Problem Statement:Using the wall as the axis of rotation, calculate the magnitude of the downward torque created by both the rod's weight and the weight of the plant.\[ \tau = \, \, \, \, \, \text{N} \cdot \text{m} \]

Answered: Image /qna-images/answer/81f1cb3f-7650-4357-9cb2-d81447740cd3.jpg

The plant in the picture has mass of 27 kg, and is hanging at a distance of 2.1 meters from the wall. The horizontal rod has mass of 6.3 kg. Assume that its weight is evenly distributed, therefore it can be treated as a single force at the center of mass. The rod is 2.8 meters long, and there is a cable at a 27° angle supporting it at the end. Using the wall as the axis of rotation, find the magnitude of the downward torque, from both the weight of the rod and the weight of the plant. N.m The downward torque is balanced by the upward torque from the force of tension. Find the magnitude of the force of tension. T = F is the contact force between the rod and the wall. Using the other horizontal force in the problem, find the horizontal component of F (the normal force) that must be present for the rod to be at equilibrium. There is a vertical force from a component of the tension, but this is not enough to balance the donward forces. Find the vertical force that must be present for the wall to keep the rod up. F, =

The plant in the picture has mass of 27 kg, and is hanging at a distance of 2.1 meters from the wall. The horizontal rod has mass of 6.3 kg. Assume that its weight is evenly distributed, therefore it can be treated as a single force at the center of mass. The rod is 2.8 meters long, and there is a cable at a 27° angle supporting it at the end. Using the wall as the axis of rotation, find the magnitude of the downward torque, from both the weight of the rod and the weight of the plant. N.m The downward torque is balanced by the upward torque from the force of tension. Find the magnitude of the force of tension. T = F is the contact force between the rod and the wall. Using the other horizontal force in the problem, find the horizontal component of F (the normal force) that must be present for the rod to be at equilibrium. There is a vertical force from a component of the tension, but this is not enough to balance the donward forces. Find the vertical force that must be present for the wall to keep the rod up. F, =

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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