FyExThe plant in the picture has mass of 22 kg,and is hanging at a distance of 1.9 metersfrom the wall. The horizontal rod has mass of9.5 kg. Assume that its weight is evenlydistributed, therefore it can be treated as asingle force at the center of mass. The rod is2.6 meters long, and there is a cable at a 23°angle supporting it at the end.Using the wall as the axis of rotation, find themagnitude of the downward torque, fromboth the weight of the rod and the weight ofthe plant.T =N•m The downward torque is balanced by theupward torque from the force of tension. Findthe magnitude of the force of tension.T =F is the contact force between the rod andthe wall. Using the other horizontal force inthe problem, find the horizontal componentof F (the normal force) that must be presentfor the rod to be at equilibrium.F.There is a vertical force from a component ofthe tension, but this is not enough to balancethe donward forces. Find the vertical forcethat must be present for the wall to keep therod up.F,N

Torque on a body is given by the cross product of force acting on it and the distance between the…

The plant in the picture has mass of 22 kg, and is hanging at a distance of 1.9 meters from the wall. The horizontal rod has mass of 9.5 kg. Assume that its weight is evenly distributed, therefore it can be treated as a single force at the center of mass. The rod is 2.6 meters long, and there is a cable at a 23° angle supporting it at the end.

The plant in the picture has mass of 22 kg, and is hanging at a distance of 1.9 meters from the wall. The horizontal rod has mass of 9.5 kg. Assume that its weight is evenly distributed, therefore it can be treated as a single force at the center of mass. The rod is 2.6 meters long, and there is a cable at a 23° angle supporting it at the end.

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Question

Fy
Ex
The plant in the picture has mass of 22 kg,
and is hanging at a distance of 1.9 meters
from the wall. The horizontal rod has mass of
9.5 kg. Assume that its weight is evenly
distributed, therefore it can be treated as a
single force at the center of mass. The rod is
2.6 meters long, and there is a cable at a 23°
angle supporting it at the end.
Using the wall as the axis of rotation, find the
magnitude of the downward torque, from
both the weight of the rod and the weight of
the plant.
T =
N•m

The downward torque is balanced by the
upward torque from the force of tension. Find
the magnitude of the force of tension.
T =
F is the contact force between the rod and
the wall. Using the other horizontal force in
the problem, find the horizontal component
of F (the normal force) that must be present
for the rod to be at equilibrium.
F.
There is a vertical force from a component of
the tension, but this is not enough to balance
the donward forces. Find the vertical force
that must be present for the wall to keep the
rod up.
F,
N

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