The pipe assembly supports the vertical loads shown. Determine the components of reaction at the ball-and-socket joint A and the tension in the supporting cables BC and BD. Given: F- 12 KN F- 6N 12 N AN

Elements Of Electromagnetics
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Free body diagram (FBD):-
The pipe assembly supports the vertical loads shown. Determine the
components of reaction at the ball-and-socket joint A and the
tension in the supporting cables BC and BD.
Given:
2m
F.- 12 kN
Equations of Equilibrium:
F- 6 kN
Converting all forces in vector form;
TBD = TEDUBD = TBD
rapl
TBD =
Tao i+
Tao j+
Tao k
1m
2m
12 kN
6 kN
TBC
Tạc = TecUBc = TBc
Page
1m 1Sm
TBc =|
Teci+ Focj+
Tac k
Transcribed Image Text:Free body diagram (FBD):- The pipe assembly supports the vertical loads shown. Determine the components of reaction at the ball-and-socket joint A and the tension in the supporting cables BC and BD. Given: 2m F.- 12 kN Equations of Equilibrium: F- 6 kN Converting all forces in vector form; TBD = TEDUBD = TBD rapl TBD = Tao i+ Tao j+ Tao k 1m 2m 12 kN 6 kN TBC Tạc = TecUBc = TBc Page 1m 1Sm TBc =| Teci+ Focj+ Tac k
Apply the equation of equilibrium, EM,-0. EM,-0 and EM,-0 and
solve the equation simultaniously
The reaction forces at point A can be eliminated by writing the
moment equation of equilibrium about point A.
Tạo
kN
IMA = 0
Tac
kN
TAB X (TBp + Tạc) + (r, xF) + (r, X F,)-0
Representing force at point A as F,=A,i + A,j+ A, k
r, is the distance from point A to F,. Since r, is directed along y axis,
therefore, r, = Oi + 4j + Ok
Then, applying the force equation of equilibrium, EF,=0, EF,=0 and
EF,=0 and solve the equation simultaniously
r, is the distance from point A to F,. Since r; is directed along y axis,
therefore, r; = 0i + 5.5j + Ok
kN
TAB
A,
kN
"Any
IMATa + Tec)x (T +Tarly (Tp +TarlelFar Fay FurM. F Fo
A.
kN
Transcribed Image Text:Apply the equation of equilibrium, EM,-0. EM,-0 and EM,-0 and solve the equation simultaniously The reaction forces at point A can be eliminated by writing the moment equation of equilibrium about point A. Tạo kN IMA = 0 Tac kN TAB X (TBp + Tạc) + (r, xF) + (r, X F,)-0 Representing force at point A as F,=A,i + A,j+ A, k r, is the distance from point A to F,. Since r, is directed along y axis, therefore, r, = Oi + 4j + Ok Then, applying the force equation of equilibrium, EF,=0, EF,=0 and EF,=0 and solve the equation simultaniously r, is the distance from point A to F,. Since r; is directed along y axis, therefore, r; = 0i + 5.5j + Ok kN TAB A, kN "Any IMATa + Tec)x (T +Tarly (Tp +TarlelFar Fay FurM. F Fo A. kN
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