The pipe assembly supports the vertical loads shown. Determinethe components of reaction at the ball-and-socket joint A and thetension in the supporting cables BC and BD.Equations of Equilibrium:Converting all forces in vector form;Given:TBp = TBDUBD = TBD2mF = 6 kNTBD =|T80 i+TBD j+F2 = 4 kN2mTBCTBc = TBCUBC = TgcIacl,1.5m1.5mTBC =Tsc i+Tscj+Tsck1m2mThe reaction forces at point A can be eliminated by writing themoment equation of equilibrium about point A.3m6 kN4 kNim 1.5m.y3mΣΜΑ-0TAB X (TBp + Tạc) + (r, x F,) + (r; x F;)= 0Free body diagram (FBD):-r, is the distance from point A to F,. Since r, is directed along y axis,therefore, r, = 0i + 4j + Okr, is the distance from point A to F2. Since r, is directed along y axis,therefore, r, = 0i + 5.5j + Ok r, is the distance from point A to F,. Since r, is directed along y axis,therefore, r, = 0i +5.5j + Okl'AB =i +IkTABX"ABY"ABzriyrzyΣΜΑ-|(TBD + TBc)x (TEp + Tgc)y (Typ + Tgc)=|*|F1x Fay F12Fayo-Apply the equation of equilibrium, EM,=0, EM,-0 and EM,=0and solve the equation simultaniouslyTBDkNIkNRepresenting force at point A as F,=A, i +A, j+A,kThen, applying the force equation of equilibrium, EF,=0, EF,=0 andEF,=0 and solve the equation simultaniouslyA,kNAy =kNkN

Fro the given Free body diagram(FBD) F1 =6 kN and F2=4 kN Now by considering A as origin the…

The pipe assembly supports the vertical loads shown. Determine Equations of Equilibrium: the components of reaction at the ball-and-socket joint A and the tension in the supporting cables BC and BD. Converting all forces in vector form; Given: Tạp = TapUBD = TBD F.= 6 kN 2m Tạp = Ta0 i+ F2= 4 kN 2m BC Tạc = TạcUBc = 1.5m Tạc =| 1m The reaction forces at point A can be eliminated by writing the moment equation of equilibrium about point A. 3m 6 kN 2m 4 kN 1m 1.5m. 3m IMA = 0

The pipe assembly supports the vertical loads shown. Determine Equations of Equilibrium: the components of reaction at the ball-and-socket joint A and the tension in the supporting cables BC and BD. Converting all forces in vector form; Given: Tạp = TapUBD = TBD F.= 6 kN 2m Tạp = Ta0 i+ F2= 4 kN 2m BC Tạc = TạcUBc = 1.5m Tạc =| 1m The reaction forces at point A can be eliminated by writing the moment equation of equilibrium about point A. 3m 6 kN 2m 4 kN 1m 1.5m. 3m IMA = 0

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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