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The pipe assembly supports the vertical loads shown. Determine Equations of Equilibrium: the components of reaction at the ball-and-socket joint A and the tension in the supporting cables BC and BD. Converting all forces in vector form; Given: Tạp = TapUBD = TBD F.= 6 kN 2m Tạp = Ta0 i+ F2= 4 kN 2m BC Tạc = TạcUBc = 1.5m Tạc =| 1m The reaction forces at point A can be eliminated by writing the moment equation of equilibrium about point A. 3m 6 kN 2m 4 kN 1m 1.5m. 3m IMA = 0

The pipe assembly supports the vertical loads shown. Determine Equations of Equilibrium: the components of reaction at the ball-and-socket joint A and the tension in the supporting cables BC and BD. Converting all forces in vector form; Given: Tạp = TapUBD = TBD F.= 6 kN 2m Tạp = Ta0 i+ F2= 4 kN 2m BC Tạc = TạcUBc = 1.5m Tạc =| 1m The reaction forces at point A can be eliminated by writing the moment equation of equilibrium about point A. 3m 6 kN 2m 4 kN 1m 1.5m. 3m IMA = 0

International Edition---engineering Mechanics: Statics, 4th Edition
International Edition---engineering Mechanics: Statics, 4th Edition
4th Edition
ISBN:9781305501607
Author:Andrew Pytel And Jaan Kiusalaas
Publisher:Andrew Pytel And Jaan Kiusalaas
Chapter10: Virtual Work And Potential Energy
Section: Chapter Questions
Problem 10.59P: The weight of the uniform bar AB is W. The stiffness of the ideal spring attached to B is k, and the...
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The pipe assembly supports the vertical loads shown. Determine the components of reaction at the ball-and-socket joint A and the tension in the supporting cables BC and BD. Equations of Equilibrium: Converting all forces in vector form; Given: TBp = TBDUBD = TBD 2m F = 6 kN TBD = |T80 i+ TBD j+ F2 = 4 kN 2m TBC TBc = TBCUBC = Tgc Iacl, 1.5m 1.5m TBC = Tsc i+ Tscj+ Tsck 1m 2m The reaction forces at point A can be eliminated by writing the moment equation of equilibrium about point A. 3m 6 kN 4 kN im 1.5m. y 3m ΣΜΑ-0 TAB X (TBp + Tạc) + (r, x F,) + (r; x F;)= 0 Free body diagram (FBD):- r, is the distance from point A to F,. Since r, is directed along y axis, therefore, r, = 0i + 4j + Ok r, is the distance from point A to F2. Since r, is directed along y axis, therefore, r, = 0i + 5.5j + Ok
Transcribed Image Text:The pipe assembly supports the vertical loads shown. Determine the components of reaction at the ball-and-socket joint A and the tension in the supporting cables BC and BD. Equations of Equilibrium: Converting all forces in vector form; Given: TBp = TBDUBD = TBD 2m F = 6 kN TBD = |T80 i+ TBD j+ F2 = 4 kN 2m TBC TBc = TBCUBC = Tgc Iacl, 1.5m 1.5m TBC = Tsc i+ Tscj+ Tsck 1m 2m The reaction forces at point A can be eliminated by writing the moment equation of equilibrium about point A. 3m 6 kN 4 kN im 1.5m. y 3m ΣΜΑ-0 TAB X (TBp + Tạc) + (r, x F,) + (r; x F;)= 0 Free body diagram (FBD):- r, is the distance from point A to F,. Since r, is directed along y axis, therefore, r, = 0i + 4j + Ok r, is the distance from point A to F2. Since r, is directed along y axis, therefore, r, = 0i + 5.5j + Ok
r, is the distance from point A to F,. Since r, is directed along y axis, therefore, r, = 0i +5.5j + Ok l'AB = i + Ik TABX "ABY "ABz riy rzy ΣΜΑ- |(TBD + TBc)x (TEp + Tgc)y (Typ + Tgc)=|*|F1x Fay F12 Fay o- Apply the equation of equilibrium, EM,=0, EM,-0 and EM,=0 and solve the equation simultaniously TBD kN IkN Representing force at point A as F,=A, i +A, j+A,k Then, applying the force equation of equilibrium, EF,=0, EF,=0 and EF,=0 and solve the equation simultaniously A, kN Ay = kN kN
Transcribed Image Text:r, is the distance from point A to F,. Since r, is directed along y axis, therefore, r, = 0i +5.5j + Ok l'AB = i + Ik TABX "ABY "ABz riy rzy ΣΜΑ- |(TBD + TBc)x (TEp + Tgc)y (Typ + Tgc)=|*|F1x Fay F12 Fay o- Apply the equation of equilibrium, EM,=0, EM,-0 and EM,=0 and solve the equation simultaniously TBD kN IkN Representing force at point A as F,=A, i +A, j+A,k Then, applying the force equation of equilibrium, EF,=0, EF,=0 and EF,=0 and solve the equation simultaniously A, kN Ay = kN kN
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