The picture on the right shows a plate capacitor. You may assume that the two plates are very large compared to the separation between the plates (i.e. you may treat them as 'infinite' planes). The plates are charged to ±Q, each plate has an area of A, and the plates are separated by a distance d. The x-axis in this problem is pointing from the negative to the positive plate, with the origin at the negative plate. The electric field at point 2 has a magnitude of E.
The picture on the right shows a plate capacitor. You may assume that the two plates are very large compared to the separation between the plates (i.e. you may treat them as 'infinite' planes). The plates are charged to ±Q, each plate has an area of A, and the plates are separated by a distance d. The x-axis in this problem is pointing from the negative to the positive plate, with the origin at the negative plate. The electric field at point 2 has a magnitude of E.
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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
Transcribed Image Text:The picture on the right shows a plate capacitor.
You may assume that the two plates are very
large compared to the separation between the
plates (i.e. you may treat them as 'infinite'
planes).
The plates are charged to +Q, each plate has an
area of A, and the plates are separated by a
distance d. The x-axis in this problem is pointing
from the negative to the positive plate, with the
origin at the negative plate. The electric field at
point 2 has a magnitude of E.
E=3000
A=1m²
d=8 mm
-Q
X=0
m
46
€0 = 8.85 x 10-12 ²
Nm²
+Q
area
A
12
·x(mm)

Transcribed Image Text:Part C:
A pith ball with mass m is hanging stationary
from a massless thread, at an angle 8. Don't
ignore gravity in this part.
m = 0.1 g 0 = 4°
a. Draw the free-body diagram (FBD) for the pith ball.
Include a coordinate system.
T
4
x=0
+Q
8
·area
A
→x(mm)
b. Set up Newton's 2nd law equations for the pith ball and use them to find the charge on the
pith ball.
c. No explanations required:
If the mass of the pith ball is increased, the tension in the string will
(i) increase (ii) decrease (iii) stay the same
If the magnitude of the charge of the pith ball is increased, the tension in the string will
(i) increase (ii) decrease (iii) stay the same
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