Help. There are more answer choices just don't know how to work the problem ### Problem 14A projectile is launched from the edge of a cliff with a velocity of 15.0 m/s at an angle of 30.0 degrees above the horizontal. Ignoring air resistance, what is the velocity of the projectile 2.00 seconds later?---To solve this problem, first break down the initial velocity into horizontal and vertical components using trigonometry:- **Horizontal component (vₓ):** \( vₓ = v \cdot \cos(\theta) \)- **Vertical component (vᵧ):** \( vᵧ = v \cdot \sin(\theta) \)Where:- \( v = 15.0 \, \text{m/s} \) is the initial velocity.- \( \theta = 30.0^\circ \) is the launch angle.### Calculation1. **Horizontal Velocity (vₓ):** \[ vₓ = 15.0 \cdot \cos(30^\circ) = 15.0 \cdot \frac{\sqrt{3}}{2} \approx 12.99 \, \text{m/s} \]2. **Initial Vertical Velocity (vᵧ₀):** \[ vᵧ₀ = 15.0 \cdot \sin(30^\circ) = 15.0 \cdot 0.5 = 7.5 \, \text{m/s} \]3. **Vertical Velocity After 2 Seconds (vᵧ):** \[ vᵧ = vᵧ₀ - g \cdot t \] Where \( g = 9.81 \, \text{m/s}^2 \) (acceleration due to gravity), and \( t = 2.00 \, \text{s} \). \[ vᵧ = 7.5 - 9.81 \cdot 2 = 7.5 - 19.62 = -12.12 \, \text{m/s} \]### Resulting VelocityTo find the magnitude of the velocity vector, use the Pythagorean theorem:\[v = \sqrt{vₓ^2 + vᵧ^2}\]\[v = \sqrt{ **Question 14:**Select the correct answer from the options below:1. 17.8 m/s at an angle of 38 degrees above the horizontal2. 11.4 m/s at an angle of 43 degrees below the horizontal3. 17.8 m/s at an angle of 43 degrees below the horizontal4. 11.4 m/s at an angle of 38 degrees above the horizontalChoose the option that best fits the scenario described in your study material and apply your understanding of projectile motion and angles in physics to determine the correct answer.

Name: Help. There are more answer choices just don't know how to work the pr
Uploaded: 2024-03-20T06:57:47.000Z
Channel: Bartleby
Description: Help. There are more answer choices just don't know how to work the problem ### Problem 14A projectile is launched from the edge of a cliff with a velocity of 15.0 m/s at an angle of 30.0 degrees above the horizontal. Ignoring air resistance, what is