A long solenoid of radius 0.400 m has N = 2000 turns and a length of 1.00 m. It is looped by the wire configuration below. The resistor has a value of 10.0 2. If the current through the solenoid windings is increasing such that 1.70 Amps/s, calculate the induced current through the resistor. The answer is in micro-Amps. Note: 1μA = 10-6 A. Express the answer to three significant digits. = (}}}]] Hint: The solenoid field is given by B = μI. Thus, the rate of change of the field is due to the rate of change of the current. And don't forget the constants when you calculate. And remember that your answer will be in microamps. R DE

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A long solenoid of radius 0.400 m has N = 2000 turns and a length of 1.00 m. It is looped by the
wire configuration below. The resistor has a value of 10.0 S. If the current through the solenoid
windings is increasing such that = 1.70 Amps/s, calculate the induced current through the
resistor. The answer is in micro-Amps. Note: 1μA = 10-6 A. Express the answer to three
significant digits.
[נונ
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www
R
Hint: The solenoid field is given by B = μI. Thus, the rate of change of the field is due to the
rate of change of the current. And don't forget the constants when you calculate. And remember
that your answer will be in microamps.
Transcribed Image Text:A long solenoid of radius 0.400 m has N = 2000 turns and a length of 1.00 m. It is looped by the wire configuration below. The resistor has a value of 10.0 S. If the current through the solenoid windings is increasing such that = 1.70 Amps/s, calculate the induced current through the resistor. The answer is in micro-Amps. Note: 1μA = 10-6 A. Express the answer to three significant digits. [נונ ( www R Hint: The solenoid field is given by B = μI. Thus, the rate of change of the field is due to the rate of change of the current. And don't forget the constants when you calculate. And remember that your answer will be in microamps.
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