The physics associated with statics has considerable applications in engineering. As a mechanical engineer working for a tow- truck manufacturer, you have been asked to evaluate the purchase of a new line of towing cable. The supplier claims that, although its cables are not as strong as its competitors (maximum tension capability of 5950 lb), the cost savings make it a good investment. A schematic of the towing configuration is shown. The car weighs 3954 lb, which is as large as the company expects their tow trucks to service. The overall length L of the car is 10.1 ft, and the distance d between the midpoints of the front and back tires is 9.09 ft. The bottom of the car's frame is a height hę = 0.370 above the ground, and the car's center of mass is a height hCM = 1.50 above the bottom of the car's frame. The angle o between the midpoint of the tires and the tow cable is 46.0°. Assume the CM of the car is positioned exactly halfway across its length, the geometry of the wheels and front/rear of the car is symmetrical, and that the coefficient of friction between the road and tires is sufficient to maintain no acceleration in the system. Calculate the tension in the cable just as the front of the car begins to lift off the ground. Assume that the front end rises at a constant velocity. СМ tension: lb

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The physics associated with statics has considerable applications in engineering. As a mechanical engineer working for a tow-truck manufacturer, you have been asked to evaluate the purchase of a new line of towing cable. The supplier claims that, although its cables are not as strong as its competitors (maximum tension capability of 5950 lb), the cost savings make it a good investment.

A schematic of the towing configuration is shown. The car weighs 3954 lb, which is as large as the company expects their tow trucks to service. The overall length \( L \) of the car is 10.1 ft, and the distance \( d \) between the midpoints of the front and back tires is 9.09 ft. The bottom of the car's frame is at a height \( h_t = 0.370 \) above the ground, and the car's center of mass is a height \( h_{CM} = 1.50 \) above the bottom of the car's frame. The angle \( \phi \) between the midpoint of the tires and the tow cable is 46.0°. Assume the CM of the car is positioned exactly halfway across its length, the geometry of the wheels and front/rear of the car is symmetrical, and that the coefficient of friction between the road and tires is sufficient to maintain no acceleration in the system.

Calculate the tension in the cable just as the front of the car begins to lift off the ground. Assume that the front end rises at a constant velocity.

Diagram Explanation:
- The car is shown with its length \( L \), and the center of mass (CM) is marked.
- The height \( h_t \) from the bottom of the car's frame to the ground and \( h_{CM} \) from the CM to the frame's bottom are labeled.
- A cable is attached at an angle \( \phi = 46.0° \).
- The distance \( d \) between the midpoint alignments of the front and back tires is identified.

Tension Calculation:
\[ \text{tension:} \ \ \ \_\_\_\_\_\_\ \ \text{lb} \]

Based on your results, what would you advise your company?
- The cable they are offering is more than adequate. The cost savings make this a worthwhile investment.
- The cable they are offering is too weak to use. I would decline the purchase.
Transcribed Image Text:The physics associated with statics has considerable applications in engineering. As a mechanical engineer working for a tow-truck manufacturer, you have been asked to evaluate the purchase of a new line of towing cable. The supplier claims that, although its cables are not as strong as its competitors (maximum tension capability of 5950 lb), the cost savings make it a good investment. A schematic of the towing configuration is shown. The car weighs 3954 lb, which is as large as the company expects their tow trucks to service. The overall length \( L \) of the car is 10.1 ft, and the distance \( d \) between the midpoints of the front and back tires is 9.09 ft. The bottom of the car's frame is at a height \( h_t = 0.370 \) above the ground, and the car's center of mass is a height \( h_{CM} = 1.50 \) above the bottom of the car's frame. The angle \( \phi \) between the midpoint of the tires and the tow cable is 46.0°. Assume the CM of the car is positioned exactly halfway across its length, the geometry of the wheels and front/rear of the car is symmetrical, and that the coefficient of friction between the road and tires is sufficient to maintain no acceleration in the system. Calculate the tension in the cable just as the front of the car begins to lift off the ground. Assume that the front end rises at a constant velocity. Diagram Explanation: - The car is shown with its length \( L \), and the center of mass (CM) is marked. - The height \( h_t \) from the bottom of the car's frame to the ground and \( h_{CM} \) from the CM to the frame's bottom are labeled. - A cable is attached at an angle \( \phi = 46.0° \). - The distance \( d \) between the midpoint alignments of the front and back tires is identified. Tension Calculation: \[ \text{tension:} \ \ \ \_\_\_\_\_\_\ \ \text{lb} \] Based on your results, what would you advise your company? - The cable they are offering is more than adequate. The cost savings make this a worthwhile investment. - The cable they are offering is too weak to use. I would decline the purchase.
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