The phosphorus in a 0.3724 g sample was precipitated as the slightly soluble (NH4)3PO4.12MoO3. this precipitate was filtered, washed, and then redissolved in acid. Treatment of the resulting solution with an excess Pb²+ resulted in the formation of 2.7346 g PbMoO4 (367.14 mol¹). Express the result as percent P40₁0 (284 gmol¹). a. 1.63 b. 34.62 c. 16.34 d. 11.83 e. 4.407

The phosphorus in a 0.3724 g sample was precipitated as the slightly soluble (NH4)3PO4.12MoO3. this precipitate was filtered, washed, and then redissolved in acid. Treatment of the resulting solution with an excess Pb²+ resulted in the formation of 2.7346 g PbMoO4 (367.14 mol¹). Express the result as percent P40₁0 (284 gmol¹). a. 1.63 b. 34.62 c. 16.34 d. 11.83 e. 4.407

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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