The phase of J2Ttf · G(T) is Select an answer and submit. For keyboard navigation, use the up/down arrow keys to select an answer. ZG(f) + T/2 for positive f and ZG(f) – T1/2 for negative f a b ZG(f) + T/2 jZG(f)for positive f and -jZG(f) for negative f d ZG(f)
The phase of J2Ttf · G(T) is Select an answer and submit. For keyboard navigation, use the up/down arrow keys to select an answer. ZG(f) + T/2 for positive f and ZG(f) – T1/2 for negative f a b ZG(f) + T/2 jZG(f)for positive f and -jZG(f) for negative f d ZG(f)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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![### More on Phase Fourier Transform
#### Review
The phase of \( j2\pi f \cdot G(f) \) is:
Select an answer and submit. For keyboard navigation, use the up/down arrow keys to select an answer.
- **a**: \(\angle G(f) + \pi/2 \) for positive \( f \) and \(\angle G(f) - \pi/2 \) for negative \( f \)
- **b**: \(\angle G(f) + \pi/2\)
- **c**: \( j\angle G(f) \) for positive \( f \) and \( -j\angle G(f) \) for negative \( f \)
- **d**: \(\angle G(f)\)
#### Correct Answer:
- ✓ **a** - \(\angle G(f) + \pi/2 \) for positive \( f \) and \(\angle G(f) - \pi/2 \) for negative \( f \)
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Transcribed Image Text:### More on Phase Fourier Transform
#### Review
The phase of \( j2\pi f \cdot G(f) \) is:
Select an answer and submit. For keyboard navigation, use the up/down arrow keys to select an answer.
- **a**: \(\angle G(f) + \pi/2 \) for positive \( f \) and \(\angle G(f) - \pi/2 \) for negative \( f \)
- **b**: \(\angle G(f) + \pi/2\)
- **c**: \( j\angle G(f) \) for positive \( f \) and \( -j\angle G(f) \) for negative \( f \)
- **d**: \(\angle G(f)\)
#### Correct Answer:
- ✓ **a** - \(\angle G(f) + \pi/2 \) for positive \( f \) and \(\angle G(f) - \pi/2 \) for negative \( f \)
[Show Submitted Answer] [Hide Correct Answer]
[Check My Answer]
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