The pH of an aqueous solution of 0.0917 M sodium fluoride, NaF, is (Assume that K₁ (HF) = 7.20 × 10¯4.) a This solution is

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The pH of an aqueous solution of 0.0917 M sodium fluoride, NaF, is [blank]. (Assume that \( K_a (\text{HF}) = 7.20 \times 10^{-4} \).)

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Transcribed Image Text:The pH of an aqueous solution of 0.0917 M sodium fluoride, NaF, is [blank]. (Assume that \( K_a (\text{HF}) = 7.20 \times 10^{-4} \).) This solution is [dropdown menu].
**Title:** Calculating the pOH of a Caffeine Solution

**Text:**

The pOH of an aqueous solution of 0.532 M caffeine (a weak base with the formula \( \text{C}_8\text{H}_{10}\text{N}_4\text{O}_2 \)) is ______. (Assume that \( K_b (\text{C}_8\text{H}_{10}\text{N}_4\text{O}_2) = 4.10 \times 10^{-4} \).)

**Graph/Diagram:**

There are no graphs or diagrams accompanying this text. 

**Explanation:**

This problem involves calculating the pOH of a caffeine solution. Given the concentration of caffeine and its base dissociation constant (\( K_b \)), you would typically use the following steps:

1. Write the equilibrium expression for caffeine ionization.
2. Use the \( K_b \) expression to solve for the hydroxide ion concentration (\( [\text{OH}^-] \)).
3. Calculate the pOH using the formula:
   \[
   \text{pOH} = -\log([\text{OH}^-])
   \]


This exercise is useful in chemistry education for understanding equilibrium expressions and the relations between pH and pOH in solution chemistry.
Transcribed Image Text:**Title:** Calculating the pOH of a Caffeine Solution **Text:** The pOH of an aqueous solution of 0.532 M caffeine (a weak base with the formula \( \text{C}_8\text{H}_{10}\text{N}_4\text{O}_2 \)) is ______. (Assume that \( K_b (\text{C}_8\text{H}_{10}\text{N}_4\text{O}_2) = 4.10 \times 10^{-4} \).) **Graph/Diagram:** There are no graphs or diagrams accompanying this text. **Explanation:** This problem involves calculating the pOH of a caffeine solution. Given the concentration of caffeine and its base dissociation constant (\( K_b \)), you would typically use the following steps: 1. Write the equilibrium expression for caffeine ionization. 2. Use the \( K_b \) expression to solve for the hydroxide ion concentration (\( [\text{OH}^-] \)). 3. Calculate the pOH using the formula: \[ \text{pOH} = -\log([\text{OH}^-]) \] This exercise is useful in chemistry education for understanding equilibrium expressions and the relations between pH and pOH in solution chemistry.
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