The pOH of an aqueous solution of 0.591 M phenol (a weak acid), C,H5OH, is

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**Problem Statement:**

Calculate the pOH of an aqueous solution of 0.591 M phenol (a weak acid), \(C_6H_5OH\).

---

**Details:**
- **Concentration of Phenol:** 0.591 M
- **Chemical Formula:** \(C_6H_5OH\)

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**Solution Approach:**

1. **Identify the dissociation reaction of phenol:** 
   Phenol (C_6H_5OH) is a weak acid, and it partially dissociates in water:
   \[ C_6H_5OH \leftrightarrow C_6H_5O^- + H^+ \]
   
2. **Determine the [H\(^+\)] concentration:** Since phenol is a weak acid, the \(K_a\) value is necessary to find the concentration of hydrogen ions (\( [H^+] \)). However, as the exact \(K_a\) is not provided in the statement, we typically use titration data or given constants to find it.

3. **Calculate the pH of the solution:**
   \[ \text{pH} = -\log [H^+] \]

4. **Convert pH to pOH:**
   \[ \text{pOH} = 14 - \text{pH} \]

---

**Note:** 
In the absence of the \(K_a\) value of phenol, the direct calculation of the pOH cannot be completed. The \(K_a\) value is crucial for the accurate determination of the hydrogen ion concentration in the solution. 

For educational purposes, ensure that you have access to the appropriate ionization constant values or refer to standard integral chemistry tables.
Transcribed Image Text:**Problem Statement:** Calculate the pOH of an aqueous solution of 0.591 M phenol (a weak acid), \(C_6H_5OH\). --- **Details:** - **Concentration of Phenol:** 0.591 M - **Chemical Formula:** \(C_6H_5OH\) --- **Solution Approach:** 1. **Identify the dissociation reaction of phenol:** Phenol (C_6H_5OH) is a weak acid, and it partially dissociates in water: \[ C_6H_5OH \leftrightarrow C_6H_5O^- + H^+ \] 2. **Determine the [H\(^+\)] concentration:** Since phenol is a weak acid, the \(K_a\) value is necessary to find the concentration of hydrogen ions (\( [H^+] \)). However, as the exact \(K_a\) is not provided in the statement, we typically use titration data or given constants to find it. 3. **Calculate the pH of the solution:** \[ \text{pH} = -\log [H^+] \] 4. **Convert pH to pOH:** \[ \text{pOH} = 14 - \text{pH} \] --- **Note:** In the absence of the \(K_a\) value of phenol, the direct calculation of the pOH cannot be completed. The \(K_a\) value is crucial for the accurate determination of the hydrogen ion concentration in the solution. For educational purposes, ensure that you have access to the appropriate ionization constant values or refer to standard integral chemistry tables.
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