The Pew Internet and American Life Project (A-13)reported in 2003 that 18 percent of Internet users haveused it to search for information regarding experimentaltreatments or medicines. The sample consisted of 1220adult Internet users, and information was collected fromtelephone interviews. We wish to construct a 95 percentconfidence interval for the proportion of Internet users inthe sampled population who have searched forinformation on experimental treatments or medicines. PlusInterpretation

INTRODUCTION : Sample proportion : Suppose we draw a sample from population with sample size n. Let…

Answered: The Pew Internet and American Life…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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A Gallup poll of 1487 adults showed that 43% of the respondents have Facebook pages. Construct a 95% confidence interval for the proportion of adults who have a Facebook page.
According to the website www.collegedrinkingprevention.gov, "About 25 percent of college students report academic consequences of their drinking including missing class, falling behind, doing poorly on exams or papers, and receiving lower grades overall." A statistics student is curious about drinking habits of students at his college. He wants to estimate the mean number of alcoholic drinks consumed each week by students at his college. He plans to use a 95% confidence interval. He surveys a random sample of 66 students. The sample mean is 3-75 alcoholic drinks per week. The sample standard deviation is 3.68 drinks. Construct the 95% confidence interval to estimate the average number of alcoholic drinks consumed each week by students at this college. Your answer should be rounded to 2 decimal places.
A Pew Research Center report on gamers and gaming estimated that 49% of U.S. adults play video games on a computer, TV, game console, or portable device such as a cell phone. This estimate was based on a random sample of 2001 U.S. adults! Construct and interpret a 95% confidence interval for the proportion of all U.S. adults who play video games. O We are 95% confident that the interval from 0.472 to 0.509 captures p = the proportion of adults in the Pew Research Center report who play video games. O We are 95% confident that the interval from 0.472 to 0.509 captures p = the true proportion of U.S. adults who play video games. We are 95% confident that the interval from 0.468 to 0.512 captures p = the true proportion of U.S. adults who play video games. O We are 95% confident that the interval from 0.468 to 0.512 captures p= the proportion of adults in the Pew Research Center report who play video games. O We are 95% confident that the interval from 0.018 to 0.031 captures p = the true…
According to a poll, 81% of California adults (410 out of 506 surveyed) feel that education is one of the top issues facing California. We wish to construct a 90% confidence interval for the true proportion of California adults who feel that education is one of the top issues facing California.What is a point estimate for the true population proportion?
According to the website www.collegedrinkingprevention.gov, "About 25 percent of college students report academic consequences of their drinking including missing class, falling behind, doing poorly on exams or papers, and receiving lower grades overall." A statistics student is curious about drinking habits of students at his college. He wants to estimate the mean number of alcoholic drinks consumed each week by students at his college. He plans to use a 90% confidence interval. He surveys a random sample of 63 students. The sample mean is 3.7 alcoholic drinks per week. The sample standard deviation is 3.2 drinks. Construct the 90% confidence interval to estimate the average number of alcoholic drinks consumed each week by students at this college. 1. The t value is - 2. The standard error has a value of -- 3. The margin of error has a value of 4. Construct the 90% confidence interval to estimate the average number of alcoholic drinks consumed each week by students at this college.
Stanford University conducted a study of whether running is healthy for men and women over age 50. During the first eight years of the study, 1.5% of the 451 members of the 50-plus Fitness Association died. We are interested in the proportion of people over 5o who ran and died in the same eight-year period. Construct a 95% confidence interval for the population proportion of people over 50 who ran and died in the same eight-year period. Explain in a complete sentence what the confidence interval means
Suppose we have only ten scores representing the ages (in years) of randomly selected U.S. commercial aircraft. The average age of the ten aircraft is 14.25 years and the sample standard deviation is 9.349 years. Construct a 95% confidence interval for the mean age of all U.S. commercial aircraft. I would appreciate to see what formulas you use and the work through because I messed up.
Obesity is defined as a body mass index (BMI) of 30 kg/m2 or more. A 95% confidence interval for the percentage of U.S. adults aged 20 years and over who were obese was found to be 20.26% to 29.8%. What was the sample size?
In a survey of 813 human resource professionals concerning challenges they faced in the workplace, 321 said that employee retention was an important challenge and 194 said that employee satisfaction was an important challenge. the 95% confidence interval estimate for the population proportion is
a critic points out that this 95 % confidence interval is only accurate if the statistic follows a normal distrubution , or if the normal model is a good approximation. is this true for this data? explain
Adults are spending more and more time on the Internet, and the number experiencing computer-based or Internet-based crime is rising. A 2018 Gallup Poll of 1019 adults, aged 18 and older, found that 723 of those in the sample said that they worry about having their personal, credit card, or financial information stolen by computer hackers. Although the samples in national polls are not SRSs, they are similar enough that our method gives approximately correct confidence intervals. Explain in words what the parameter p is in this setting ? Use the poll results to give a 95% confidence interval for p.
I chose Option 1 for this week’s discussion post. I want to estimate the population mean number of times adults between the ages of 30 and 45 went to the grocery store in the last week. I spoke with 12 adults and asked them how many times they went to the grocery store in the last week. The results were 0, 2, 2, 7, 5, 1, 0, 3, 1, 1, 4, and 3. Now calculate a 95% confidence interval for the population mean. (Round to three decimal places)

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