The perpendicular distance between two parallel tangents of a reversed curve is 40m. The azimuth of the back tangent of the curve is 270° and the azimuth of the common tangent is 300°. If the radius of the back curve is 165m, and the station of the PRC is 20+115, find the station at PT. Solve by arc basis.

Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
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The topic is reverse curve. 

A. Problem 2
The perpendicular distance between two parallel tangents of a reversed curve
is 40m. The azimuth of the back tangent of the curve is 270° and the azimuth of the
common tangent is 300°. If the radius of the back curve is 165m, and the station of the
PRC is 20+115, find the station at PT. Solve by arc basis.
Transcribed Image Text:A. Problem 2 The perpendicular distance between two parallel tangents of a reversed curve is 40m. The azimuth of the back tangent of the curve is 270° and the azimuth of the common tangent is 300°. If the radius of the back curve is 165m, and the station of the PRC is 20+115, find the station at PT. Solve by arc basis.
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