Please show all steps to solve this problem so your thought process is easy to follow. Also please show all formulas that you used. Subject is fluid mechanics **Question 5****Problem Statement:**Determine the resultant magnitude of the hydrostatic force that water exerts on the wall along the surface \(ABC\). The wall is \(15 \, \text{ft}\) wide (into the page). \(AB\) is a circular arc of radius \(3 \, \text{ft}\) and the length of \(BC\) is \(2 \, \text{ft}\).**Diagram Explanation:**- The diagram depicts a cross-section of a water tank.- A person is standing at the top of the tank next to point \(C\).- The water surface is represented by a horizontal dashed line from point \(C\) to the other side.- \(AB\) is a circular arc with a radius of \(3 \, \text{ft}\) reaching from point \(A\) at the bottom left of the circular portion to point \(B\) beside the straight wall section.- The length \(BC\) is a vertical straight line segment on the right-hand wall of \(2 \, \text{ft}\).- The water extends over the entire surface area, exerting hydrostatic force on it. **Key Measurements:**- The radius of the arc \(AB\) is \(3 \, \text{ft}\).- The vertical length \(BC\) is \(2 \, \text{ft}\).- The width of the wall into the page is \(15 \, \text{ft}\).

Solution:- Given data:- The width of wall (b) = 15 ft radius of arc (r) = 3 ft Length (L) = 2 ft To find:- The resultant magnitude of the hydrostatic force. Calculation:- Now, Calculating the horizontal component of hydrostatic force. FH = γ × A × hWhere,A = projected area∴ A = B×D ...(D =2+3 =5)∴ A = 15×5 = 75 ft2h = Centroidal distanceh =2+32=2.5 fttherefore,Assume = γ = 62.4 lb/ft3FH = γ × A × h∴ FH =62.4 × 75 × 2.5∴ FH =11718.75 lbNow, Vertical component of hydrostatic force. quadrantal Fv = Weight of liquid above curved surface to free surface.Here,AB is quadrantal arc i.e. area of sector is 1/4 of circle.Fv =π×(d)24+(B×L)× b × 62.4Fv =π×(3)24+(3×2)×15×62.4Fv =12232.19 lb Now,The resultant magnitude of the hydrostatic force.F = F2H +F2V ∴ F =(11718.75)2+(12232.19)2∴ F =16939.6 lbConclusion:- The resultant magnitude of the hydrostatic force = 16939.6 lb