The perpendicular distance between two parallel tangents is equal to 8m, central angle equal to 8° and the radius of curvature of the first curve equal to 175m. 10. Find the radius of the second curve of the reversed curve.

The perpendicular distance between two parallel tangents is equal to 8m, central angle equal to 8° and the radius of curvature of the first curve equal to 175m. 10. Find the radius of the second curve of the reversed curve.

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Concept explainers

Control Survey and Geodetic reductions

Control surveys or survey controls are used to establish reference points as a basis for various construction activities. Vertical and horizontal control points are to be established in a control survey to increase accuracy. After establishing the control points, all other types of surveys such as topographic, right-of-way, aerial mapping, construction layout, boundary surveys, and utility mapping can be worked upon so that control networks can be formed. The place from which the observations are made is called a survey station.

Question

The perpendicular distance between two parallel
tangents is equal to 8m, central angle equal to 8°
and the radius of curvature of the first curve
equal to 175m.
10. Find the radius of the second curve of the
reversed curve.

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A simple curve connects two tangents AB and BC with bearings N 85°30'00" E and S 68°30'00"E, respectively. If the stationing of B is 4+360.2, and the stationing of PC is 4+288.4, determine the following: a. Radius Answer: R= b. External Distance Answer: E= c. Middle Ordinate Answer: M= d. Chord Distance Answer: Lc= e. Length of Curve Answer: L= m m m m E
Given for a compound curve: plus of PI = 14 + 29.31 , Δ = 97 ° 35 ′ 15 ″ ; the first radius R 1 = 400 ′ , Δ 1 = 63 ° 22 ′ 18 ″ , R 2 = 800 ′ . Compute the pluses of PC, PCC, and PT and the length
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3. The tangents of a simple curve have bearings of N 20 degrees E and N 80 degrees E respectively. The radius of the curve is 200 m. a. Compute the stationing of point A on the curve having a deflection angle of 6 degrees from the P.C which is at 1+200.00.
QUESTION 2 The tangent thru the PC has a direction due to North; and the tangent through the PT has a bearing of N 50° E. It has a radius of 200 m. Stationing of PC is 12+060. a. Compute the tangent distance of the curve. Answer: T= b. Compute the long chord of the curve. Answer: Lc = m m c. A line is drawn from the center of the curve (at the central angle) and intersects the curve at point B. This line, when extended, makes an angle of 62° with the tangent thru PC. What is the stationing of point B? Answer: Sta. B = Note: Unit has been provided after the blank space. No need to indicate units on your answer.
4. A parallel reversed curve has an equal radius of 360m and a central angle of 8º. a. Compute the distance between parallel tangents b. Compute the length of the Chord from PC to PT If Sta PC = 3 +960.40, what is Sta PT? C.
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