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The percent by mass of manganese(II) in Mn3(PO4)2 %. is

The percent by mass of manganese(II) in Mn3(PO4)2 %. is

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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**Title: Calculating the Percent by Mass of Manganese(II) in Mn₃(PO₄)₂** **Introduction:** In this exercise, we aim to calculate the percent by mass of manganese(II) in the chemical compound Mn₃(PO₄)₂. **Instructions:** To find the percent by mass of manganese(II), follow these steps: 1. **Determine the Molar Mass of Each Element:** - Manganese (Mn): Approximately 54.94 g/mol - Phosphorus (P): Approximately 30.97 g/mol - Oxygen (O): Approximately 16.00 g/mol 2. **Calculate the Molar Mass of Mn₃(PO₄)₂:** - Mn₃: 3 × 54.94 g/mol = 164.82 g/mol - PO₄: (30.97 + 4 × 16.00) g/mol = 94.97 g/mol - Mn₃(PO₄)₂ = 164.82 + 2 × 94.97 = 354.76 g/mol 3. **Calculate the Percent by Mass of Manganese(II):** - Total mass of Mn in Mn₃(PO₄)₂ = 164.82 g/mol - Percent by mass of Mn = (164.82 g/mol ÷ 354.76 g/mol) × 100% **Interactive Component:** - Use the text box provided to input your calculated percent by mass of manganese(II). - Verify your answer for correct understanding and application of chemical calculations. **Reflection:** Understanding how to calculate the percent by mass of an element within a compound is a crucial skill in chemistry, especially in analytical and industrial applications.
Transcribed Image Text:**Title: Calculating the Percent by Mass of Manganese(II) in Mn₃(PO₄)₂** **Introduction:** In this exercise, we aim to calculate the percent by mass of manganese(II) in the chemical compound Mn₃(PO₄)₂. **Instructions:** To find the percent by mass of manganese(II), follow these steps: 1. **Determine the Molar Mass of Each Element:** - Manganese (Mn): Approximately 54.94 g/mol - Phosphorus (P): Approximately 30.97 g/mol - Oxygen (O): Approximately 16.00 g/mol 2. **Calculate the Molar Mass of Mn₃(PO₄)₂:** - Mn₃: 3 × 54.94 g/mol = 164.82 g/mol - PO₄: (30.97 + 4 × 16.00) g/mol = 94.97 g/mol - Mn₃(PO₄)₂ = 164.82 + 2 × 94.97 = 354.76 g/mol 3. **Calculate the Percent by Mass of Manganese(II):** - Total mass of Mn in Mn₃(PO₄)₂ = 164.82 g/mol - Percent by mass of Mn = (164.82 g/mol ÷ 354.76 g/mol) × 100% **Interactive Component:** - Use the text box provided to input your calculated percent by mass of manganese(II). - Verify your answer for correct understanding and application of chemical calculations. **Reflection:** Understanding how to calculate the percent by mass of an element within a compound is a crucial skill in chemistry, especially in analytical and industrial applications.
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