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The path r(t) = (t)i + (+²+6) j describes motion on the parabola y=x² +6. Find the particle's velocity and acceleration vectors at t= and sketch them as vectors on the curve. The velocity vector at t= -3 is v(-3)= | (Simplify your answer, including any radicals. Use integers or fractions for any numbers in the expression.) The acceleration vector at t= -3 is a(-3)=( İ+ (Simplify your answer, including any radicals. Use integers or fractions for any numbers in the expression.) Choose the correct sketch for the particle's velocity and acceleration at t= -3. O A. OB. OC. V

The path r(t) = (t)i + (+²+6) j describes motion on the parabola y=x² +6. Find the particle's velocity and acceleration vectors at t= and sketch them as vectors on the curve. The velocity vector at t= -3 is v(-3)= | (Simplify your answer, including any radicals. Use integers or fractions for any numbers in the expression.) The acceleration vector at t= -3 is a(-3)=( İ+ (Simplify your answer, including any radicals. Use integers or fractions for any numbers in the expression.) Choose the correct sketch for the particle's velocity and acceleration at t= -3. O A. OB. OC. V

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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The path r(t) = (t)i + (t²+6) j describes motion on the parabola y = x² +6. Find the particle's velocity and acceleration vectors at t= -3, and sketch them as vectors on the curve. The velocity vector at t= -3 is v(-3) = ( j. (Simplify your answer, including any radicals. Use integers or fractions for any numbers in the expression.) İ+ j. The acceleration vector at t= -3 is a(-3)=([ (Simplify your answer, including any radicals. Use integers or fractions for any numbers in the expression.) Choose the correct sketch for the particle's velocity and acceleration at t= -3. O A. B. OC. . . .
Transcribed Image Text:The path r(t) = (t)i + (t²+6) j describes motion on the parabola y = x² +6. Find the particle's velocity and acceleration vectors at t= -3, and sketch them as vectors on the curve. The velocity vector at t= -3 is v(-3) = ( j. (Simplify your answer, including any radicals. Use integers or fractions for any numbers in the expression.) İ+ j. The acceleration vector at t= -3 is a(-3)=([ (Simplify your answer, including any radicals. Use integers or fractions for any numbers in the expression.) Choose the correct sketch for the particle's velocity and acceleration at t= -3. O A. B. OC. . . .
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