The particles inside the mist are disordered as in figure 2. Let's try to get an idea of how this mist behaves under the effect of electrical interactions. To simplify the discussion, we will focus on a droplet located in the central region and a droplet located at the periphery of the mist, and compare the forces they are subjected to. The positions of the two droplets are named A and B, respectively, in figure 2a). а) b) c) A 2 mm 22° 1.5 mm B B. of
The particles inside the mist are disordered as in figure 2. Let's try to get an idea of how this mist behaves under the effect of electrical interactions. To simplify the discussion, we will focus on a droplet located in the central region and a droplet located at the periphery of the mist, and compare the forces they are subjected to. The positions of the two droplets are named A and B, respectively, in figure 2a). а) b) c) A 2 mm 22° 1.5 mm B B. of
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Transcribed Image Text:The particles inside the mist are disordered as in figure 2. Let's try to get an idea of how this mist behaves
under the effect of electrical interactions. To simplify the discussion, we will focus on a droplet located in the
central region and a droplet located at the periphery of the mist, and compare the forces they are subjected
to. The positions of the two droplets are named A and B, respectively, in figure 2a).
a)
b)
c)
93
A
A
2 mm
22°
1.5 mm
B
FIGURE 2 – a) A mist of droplets was sprayed. We will focus on two particular regions outlined in the figure.
b) Zoom on the central part of the mist. c) Zoom on droplet B.
Let us first estimate the forces exerted by the droplets located in the blue dotted rectangle around the
droplet placed in the center of the mist in A. To simplify from now on, the droplets will be designated by
their charge. The droplet placed in A and of charge q4 will just be called a charge q4.
1. Calculate the intensity of the force F1 exerted by droplet q1 on droplet q4. The charges are given as
qA = 20 pC and q1 = 15 pC. In figure 2b), the tiles of the grid are 1 mm square. The answer must be
justified because the charges qa and q1 are not point charges. Care should be taken to give the literal
expression before making the numerical application.
2. Represent this force to scale on the diagram in Appendix 1 to be handed in with your homework.
3. Give the expression of the force F2 exerted by the charge q2 on the charge qa. Calculate its intensity
knowing that the value of the charge q2 is q2 = 59.3 pC, and represent it on the diagram in Appendix 1.
4. Plot the total force F12 exerted by the charges q1 and q2 on the charge qa.
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