The overall redox reaction for a given galvanic cell is 2H+ (aq) + Fe(s)→→→→→Fe²+ (aq) + H₂(g). Determine the value of Ecell when the reaction conditions are: T= 298 K pH = 4.00 [Fe2+] = 1.1 M PH2 = 0.750 atm Fe2+ (aq) + 2e Fe(s) → Eº cell = -0.447 V Enter your answer in volts and with two digits to the right of the decimal.

Chemistry
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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
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The overall redox reaction for a given galvanic cell is:

\[ 2\text{H}^+(aq) + \text{Fe}(s) \rightarrow \text{Fe}^{2+}(aq) + \text{H}_2(g) \]

Determine the value of \( E_{\text{cell}} \) when the reaction conditions are:

- \( T = 298 \, K \)
- \( \text{pH} = 4.00 \)
- \( [\text{Fe}^{2+}] = 1.1 \, M \)
- \( P_{\text{H}_2} = 0.750 \, \text{atm} \)

The half-reaction is given by:

\[ \text{Fe}^{2+}(aq) + 2e^- \rightarrow \text{Fe}(s) \]

With an \( E^\circ_{\text{cell}} = -0.447 \, V \).

**Instruction:**

Enter your answer in volts and with two digits to the right of the decimal.

**Possible Answers:**

- 0.214 (with margin: 0)
- 0.212 (with margin: 0)
- 0.213 (with margin: 0)
Transcribed Image Text:The overall redox reaction for a given galvanic cell is: \[ 2\text{H}^+(aq) + \text{Fe}(s) \rightarrow \text{Fe}^{2+}(aq) + \text{H}_2(g) \] Determine the value of \( E_{\text{cell}} \) when the reaction conditions are: - \( T = 298 \, K \) - \( \text{pH} = 4.00 \) - \( [\text{Fe}^{2+}] = 1.1 \, M \) - \( P_{\text{H}_2} = 0.750 \, \text{atm} \) The half-reaction is given by: \[ \text{Fe}^{2+}(aq) + 2e^- \rightarrow \text{Fe}(s) \] With an \( E^\circ_{\text{cell}} = -0.447 \, V \). **Instruction:** Enter your answer in volts and with two digits to the right of the decimal. **Possible Answers:** - 0.214 (with margin: 0) - 0.212 (with margin: 0) - 0.213 (with margin: 0)
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