### Force Acting on a BodyThe only force acting on a 1.5 kg body as it moves along the \( x \)-axis varies as shown below. The scale of the figure's vertical axis is set by \( F_s = 4.4 \) N. The velocity of the body at \( x = 0 \) is 4.1 m/s.#### Force vs. Displacement GraphThe graph below shows the relationship between the force \( F_x \) (in Newtons) and the displacement \( x \) (in meters).- **X-Axis (Displacement \( x \))**: Ranges from 0 m to 5 m.- **Y-Axis (Force \( F_x \))**: Ranges from \(-F_s\) to \(F_s\) (\(-4.4 \text{ N}\) to \(4.4 \text{ N}\)).The force decreases linearly from \( F_s \) (4.4 N) at \( x = 0 \) to 0 at \( x = 1 \) m. It then stays at 0 from \( x = 1 \) m to \( x = 5 \) m.![Graph]#### Problem(a) What is the kinetic energy of the body at \( x = 3.0 \) m?**Solution:**\[ K.E. = -4.4 \text{ J} \](Note: The provided solution of \(-4.4 \text{ J}\) is indicated to be incorrect.)---This educational material is designed to help students understand how force varies with displacement and how it affects the kinetic energy of a moving body.

Name: ### Force Acting on a BodyThe only force acting on a 1.5 kg body as i
Uploaded: 2024-03-20T06:57:25.000Z
Channel: Bartleby
Description: ### Force Acting on a BodyThe only force acting on a 1.5 kg body as it moves along the \( x \)-axis varies as shown below. The scale of the figure's vertical axis is set by \( F_s = 4.4 \) N. The velocity of the body at \( x = 0 \) is 4.1 m/s.#### F

Answered: Image /qna-images/answer/1c33e60c-60f1-4daf-805a-324ab9bf8977.jpg

Science

Physics

The only force acting on a 1.5 kg body as it moves along the axis varies as shown below. The scale of the figure's vertical axis is set by F = 4.4 N. The velocity of the body at x = 0 is 4.1 m/s. Fx (N) KED 1 2 3 4 5 F 0 x (m) (a) What is the kinetic energy of the body at x = 3.0 m? -4.4 X J

The only force acting on a 1.5 kg body as it moves along the axis varies as shown below. The scale of the figure's vertical axis is set by F = 4.4 N. The velocity of the body at x = 0 is 4.1 m/s. Fx (N) KED 1 2 3 4 5 F 0 x (m) (a) What is the kinetic energy of the body at x = 3.0 m? -4.4 X J

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

See similar textbooks

Similar questions

If the force in the figure below is the net force on the particle, find the change in the particle's kinetic energy as it moves as follows. Fx (N) 12.0 x (m) 3.0 6.0 9.0 12.0 -12.0 (a) From x; = 0 to xf = 6.0 m 24 Your response differs from the correct answer by more than 10%. Double check your calculations. J (b) From x; = 6.0 to Xf = = 12.0 m |-48 Your response differs from the correct answer by more than 10%. Double check your calculations. J (c) From x; = 0 to xf = = 12.0 m %3D -24 Your response differs from the correct answer by more than 10%. Double check your calculations. J
The only force acting on a 4.0 kg body as the body moves along an x axis varies as shown in the figure. The scale of the figure's vertical axis is set by F = 8.0 N. The velocity of the body at x = 0 is 8.0 m/s. (a) What is the kinetic energy of the body at x = 5.0 m? (b) At what value of x will the body have a kinetic energy of 65.0 J? (c) What is the maximum kinetic energy of the body between x = 0 and x = 5.0 m? F, (N) FN 3 4 x (m) -F,
A particle moving along the x-axis is in a system Part B ▼ with potential energy U = 11/x J, where x is in m. What is the x-component of the force on the particle at x = 5 m? Express your answer to two significant figures and include the appropriate units. HẢ ? Fx = Value Units
Jeanine used 250 J of energy to lift a 15 kg box. How far did she lift the box? А 1.7 m 3.8 m 17 m 380 m
A 2000 kg car with a 250 HP (1.865 X 105 W) engine accelerates from rest. If all the engine’s power is used to change the car’s speed during the entire trip, how much time does it take for the car to reach 100 mph (44.7 m/s)? Group of answer choices 10.7 s 4.81 s 6.78 s 15.1 s
Pushing the cart adds 40 J to the system, and 12 J of energy is lost. The change in energy in the system is 153 J. What was the additional amount of work added to the system? Eƒ = E; + AW + AQ
The graph below shows the force applied to a 2.0 kg body, initially at rest but free to move along a straight line on a horizontal frictionless surface. The force acts along the same straight line. After the body has moved 3 m, what is its kinetic energy?
A 4.32-kg particle is subject to a net force that varies with position as shown in the figure. The particle starts from rest at x = 0. Fx (N) n 2 4 6 8 10 12 14 16 2 19 1 What is its speed at the following positions? (a) x = 5.00 m (b) x = 10.0 m (c) x = 15.0 m m/s m/s m/s x (m)
A stone of mass 1.0 kg is dropped from rest at the top of a 100.0 meter high building. Assume there is no air resistance. What is the kinetic energy of the stone just before it strikes the ground? The following numerical values may be helpful in this question. G = 6.67 ∙10-11 N∙m2/ kg2 Earth’s mass = 5.98 · 1024 kilograms g = 9.80 m/sec2 1 kilometer = 1000 meters
A child stands on a bank beside a pond, grasps the end of a 20.0 m long rope attached to a nearby tree and swings out to drop into the water. When the rope makes an angle of 15.0⁰ with the vertical, the child's speed is 5.00 m/s. a) At what point in the swing does the child's maximum speed occur? b) What is the child's maximum speed? Ignore all frictional effects. c) Assuming the child started from rest, what angle did the rope initially make with respect to the vertical?
Plz answer all parts asap
A 12.5-kg crate slides along a horizontal frictionless surface at a constant speed of 4.0 m/s. The crate then slides down a frictionless incline and across a second horizontal surface as shown in the figure. 4.0 m/s Reference: Ref 6-5 3.0 m 4.0m What is the kinetic energy of the crate as it slides on the lower surface? ○290J 320 J 370 J 0470 J O570 J