The number of fully formed apples on 100 plants were counted with following results: Plants had apple 1 7 2 apples 11 3 It 18 4 24 12 8 7 II 8 4 9 II 3 10 (i) How many apples were there in all? (i) What was the average number of apples per plant? (ii) - What was the modal number of apples? LO CO %3D %3D N 5

Q: C. In a week, there are 10 clinic sessions - how many patients would you expect to fail to show up?

A: It is given that n =10 and p =0.25.

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A: Here AS PER POLICY I HAVE CALCULATED 3 SUBPARTS PLZ REPOST FOR REMAINING PARTS HERE given, A…

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A: We have to solve given Questions.

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A: Given that, Scores (X): 4, 1, 6, 5 Calculate (X-4):

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A:

Q: (468)10=

A:

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A:

Q: Evaluate.

A: ∑k=1106-12k

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A: To fill the blank and apply the property of addtition_+9=98+3+2=_+3+2_+6=6+4

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A: Given info: A standard deck of cards contains 52 cards. One card is selected from the deck.

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A: Given mn=3m-n

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A:

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A: Explained below

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A:

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A:

Q: If P(A) = 0.009, what is the value of P(A)? P(A) = (Type an integer or a decimal. Do not round.)

A: Given, p(A) = 0.009 We will use complement probability of A.

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A:

Q: Given P(A) = 0.3 and P(B) = 0.4; if P(A and B) = 0.1, compute P(A or B)

A: From the provided information, P (A) = 0.3, P (B) = 0.4 and P (A and B) = 0.1

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A: Let's assume the number of red cards Ben had initially is "R,,"child-0-0">Let's assume the number…

Q: If P(A) = 0.35, P(B) = 0.45, and P(A and B) = 0.25, then P(A|B) is:     1.4     1.8     0.714…

A: P(A)=0.35 P(B)=0.45 P(A and B)=0.25   P(A/B)=P(A and B)P(A)=0.250.35=0.714

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A:

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Q: 7

A:

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A: given data P(drank alcohole) = p = 710 = 0.7sample size(n) = 10x = no. of students drank alcoholeσx…

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A:

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A: The values of X are given by 3,6 and 9. We have to calculate Σ(X – 2 )2

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A: We have to find the value of: (0.1)3 (20)3

Q: Given that P = (3 -4) and Q = (-2 1)                          (7 6)                ( 0 5) Calculate:…

A: To Calculate:a) ½(P)b) 1/3(Q)c) 1/2(P) + 1/3(Q)d) ½(P) – 1/3(Q)e) 1/3(Q) – ½(P)

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A:

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A: Given:p = population proportion = 35% or 0.35 n = 441Note:The sampling distribution of the…